1 mole of phosphoric acid (H3PO4) and 1.75 moles of NaOH are added to the one liter water. Calculate the pH.

1 answer:

6 0

Moles of H⁺ released by each mole of acid = 3
Moles of H⁺ released = 3

Moles of OH⁻ released = 1.75

Moles of H⁺ remaining = 3 - 1.75 = 1.25 mol/dm³

pH = -log[H⁺]
pH = -log(1.25)
pH = -0.1

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