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choli [55]
3 years ago
9

A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver’s velocity re

mains constant. What is the work done by the nonconservative force of air resistance, which is the only nonconservative force acting?
Physics
1 answer:
Alborosie3 years ago
5 0

Answer:

The work done is 293.0kJ

Explanation:

<u>Data</u>

  • Mass:   m=92.0kg
  • height:    h=325m
  • acceleration due to gravity:  g=9.81m/s^{2}

Non conservative force act

The work is:

W=ΔKE+ΔPE

KE and PE means kinetic energy and potential energy respectively.

The change in kinetic energy is 0, since the skydiver’s velocity remains constant.

Therefore

W=0+ΔPE

W=ΔPE

W=mgh

substitute the values

W=92.0kg*9.81m/s^{2} *325m\\W=293020J\\W=293.0kJ

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