Answer: 120.9 grams
Explanation:
Given the question : How many grams are in 3.67 moles of Lithium cyanide?
Chemical formula of lithium cyanide = LiCN
Molar mass of LiCN: Li = 6.941 ; C = 12, N = 14
LiCN = (6.941 + 12 + 14). = 32.941 g/mol
(Gram of substance / mole of substance) = (molar mass of substance / one mole)
(Gram of substance / 3.67) = (32.941 / 1)
= gram * 1 = 3.67 * 32.941
Gram of substance = 120.89347
= 120.9 grams
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Answer:
different from ionic or covalent bonding
Explanation:
Answer:
Explanation:
Hello,
In this case, considering that the density is considered as the quotient of the mass and volume:
We can easily compute the mass by solving for it as follows:
Best regards.
Answer:
A. 3.7 x 10⁻³
Explanation:
In the beginning of the reaction there are 0.200 moles of reactant. After 25 minutes, remain 0.108 moles. That means the moles that wer descomposed are:
0.200 moles - 0.108 moles = 0.092 moles of reactant were descomposed.
That descomposition occurs in 25 minutes. The average rate of descomposition in moles / minute are:
0.092 moles Methyl isonitrile / 25 minutes = 3.7x10⁻³ mol/min.
Right option is:
<h3>A. 3.7 x 10⁻³</h3>
