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aev [14]
3 years ago
6

The results of a dart game were precise but not accurate.The accepted value of the game was the center of the dartboard.Which co

rrectly describes the results.
A. All of the darts hit the center of the board
B.Some of the darts hit the center of the board
C.The darts hit the same general area of the board
D.The darts hit very different areas of the board
Physics
2 answers:
Vlada [557]3 years ago
8 0

Answer:

The darts hit the same general area of the board.

Aleksandr-060686 [28]3 years ago
4 0

Answer: C. The darts hit the same general area of the board.

Explanation: The results of a dart game were precise but not accurate. The accepted value of the game was the center of the dartboard.

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A caterpillar crawls 20 feet in 5 minutes. What is the caterpillars crawling speed?
Pavel [41]
The equation is
s= d/t

In this case you would have to write it out as:
s= 20/5
Speed = 4
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3 years ago
When you turn on a lightbulb in a room, the entire room appears to flood with light at the same time. Your eyes cannot perceive
Evgen [1.6K]

Explanation:

Assuming we can turn on the lightbulb from any distance with a device. We can gradually increase the distance that separates us from lightbulb, in this way, if the speed of light is finite  we can see a temporary delay between the moment we turn on the lightbulb and the moment in which we observe its light.

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3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

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3 0
2 years ago
You input 75 J of work with a wedge. If the wedge does 65 J of useful work, what if the efficiency of the wedge ?
zavuch27 [327]

Answer:

Efficiency of wedge is the ratio of "work done by the machine to the work supplied to the machine".

           Efficiency (η) = Work done by machine ÷ Work supplied

                                  = 65 ÷ 75

                                 = 0.86%

<em>Efficiency of wedge is 86%</em>

5 0
3 years ago
What type of units can be used for measurement?
Anna35 [415]

Answer:

Measurements most commonly use the International System of Units (SI) as a comparison framework. The system defines seven fundamental units: kilogram, metre, candela, second, ampere, kelvin, and mole.

3 0
3 years ago
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