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3 years ago

Water can form large dewdrops in nature how would droplets made of vegetable oil instead of water be different

Physics

2 answers:

Jlenok [28]3 years ago

6 0

Answer:

Explanation:

Natasha2012 [34]3 years ago

3 0

Answer:d

Explanation: oil would form droplets but only tiny ones because it’s surface tension is lower than that of water

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Points a, b, and c are at the corners of an equilateral triangle of side 1 m. equal positive charges of 5 c are at a and

soldier1979 [14.2K]

Solution:

we know that the potential of any point is given by

v= kq/r^2............(1)

According to the question we have point charges is applied only two point so we must multiply the above equation by 2.

Then we get

V=2kq/r^2 [since charge is unity].

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3 years ago

A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. If it takes 0.070 N of force to keep the b

gulaghasi [49]

Tangential speed= 0.68 m/s

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3 years ago

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In the Bohr model of the hydrogen atom, the electron moves in a circular orbit of radius 5.3×10−11m with a speed of 2.2×106m/s.

lisov135 [29]

Answer:

The magnitude of the electric field is 512171146711.7046 N/C.

The direction is toward the electron as electron has negative charge.

Explanation:

e = Charge of electron = $1.6\times 10^{-19}\ C$

r = Radius of circular orbit = $5.3\times 10^{-11}\ m/s$

$\epsilon_0$ = Permittivity of free space = $8.85\times 10^{-12}\ F/m$

The Electric field is given by

$E=\frac{e}{4\pi\epsilon_0 r^2}\\\Rightarrow B=\frac{1.6\times 10^{-19}}{4\pi\times 8.85\times 10^{-12}\times (5.3\times 10^{-11})^2}\\\Rightarrow E=512171146711.7046\ N/C$

The magnitude of the electric field is 512171146711.7046 N/C.

The direction is toward the electron as electron has negative charge.

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3 years ago

In a material for which o=5.0 S/m and e, =1 the electric field intensity is E- 250 sin 10" (V/m). Find the conduction and displa

Elodia [21]

Answer:

Explanation:

Given that:

The conductivity of the material $\sigma$ = 5.0 s/m

$The \ relative \ permittivity \ of \ the \ material$ ${\varepsilon_r} = 1$ ; &

The electric field intensity of the material E = 250 sin(10¹⁰ t) V/m

(a) The conduction current density $( J_c) = \sigma E$

$= 5.0 \times 250 \ sin ( 10^{10} \ t )$

$\mathbf{ = 1250 \ sin (10 ^{10} t ) \ A/m^2 }$

(b) Displacement current density $(J_d) = \varepsilon _d * \dfrac{\delta E}{\delta t}$

Recall that:

$\varepsilon _o = 8.854 \times 10^{-12}$

∴

$(J_d) = 8.854 \times 10^{-12} \times \dfrac{d}{dt} \times (250 \ sin \ (10^{10} \ t))$

$(J_d) = 8.854 \times 10^{-12} \times 250 \times 10^{10} \times \ cos \ (10^{10} \ t)$

$(J_d) = 22.135 \ cos \ 10^{10} \ t \ A/m^2$

$f = \dfrac{\sigma}{2 \pi \varepsilon_o \varepsilon_r}$

By substitution

$f = 18 \times 10^9 \times \dfrac{\sigma }{\varepsilon_r}$

$f = 18\times 10^9 \times \dfrac{5}{1 }$

f = 90 GHz

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3 years ago

A baby and stroller have a total mass of

klio [65]

We know that the formula for the centripetal force is:

F = m·v² / r

Solving for v we get:

v = √(F · r / m)
= √(36 N · 5.0 m / 20 kg)
= 3.0 m/s

The stroller moves at a speed of <span>3.0 m/s.</span>

5 0

4 years ago

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