Solution:
we know that the potential of any point is given by
v= kq/r^2............(1)
According to the question we have point charges is applied only two point so we must multiply the above equation by 2.
Then we get
V=2kq/r^2 [since charge is unity].
Answer:
The magnitude of the electric field is 512171146711.7046 N/C.
The direction is toward the electron as electron has negative charge.
Explanation:
e = Charge of electron = 
r = Radius of circular orbit = 
= Permittivity of free space = 
The Electric field is given by

The magnitude of the electric field is 512171146711.7046 N/C.
The direction is toward the electron as electron has negative charge.
Answer:
Explanation:
Given that:
The conductivity of the material
= 5.0 s/m
; &
The electric field intensity of the material E = 250 sin(10¹⁰ t) V/m
(a) The conduction current density 


(b) Displacement current density 
Recall that:

∴



(c) The frequency at which
will have the same magnitude is:

By substitution


f = 90 GHz
We know that the formula for the centripetal force is:
F = m·v² / r
Solving for v we get:
v = √(F · r / m)
= √(36 N · 5.0 m / 20 kg)
= 3.0 m/s
The stroller moves at a speed of <span>3.0 m/s.</span>