(i feel so dumb )

2. A mixing bowl has a mass of 0.5kg. A baker adds 0.0002m of water to the mixing bowl until

myrzilka [38]

Answer:

mass of water is 0.2kg

Explanation:

mass of water is tota mass of bowl minus mass of bowl

6 0

2 years ago

Cual es la fuerza electrica sobre el electrón (-1.6 x 10¹⁹c) de un atomo de hidrógeno ejercida por el protón (1.6 x 10¹⁹c)? Supó

kkurt [141]

Answer:

La fuerza eléctrica es -8.2*10⁻⁸ N

Explanation:

El enunciado correcto es: ¿Cuál es la fuerza eléctrica sobre el electrón (-1.6 x 10⁻¹⁹c) de un átomo de hidrógeno ejercida por el protón (1.6 x 10⁻¹⁹c)? Supóngase que la distancia entre el electrón y el protón es de 5.3 x 10⁻¹¹ m

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica. Su valor depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga. Las cargas del mismo signo se repelen entre sí, mientras que las de distinto signo se atraen.

La fuerza eléctrica con la que se atraen o repelen dos cargas puntuales en reposo es directamente proporcional al producto de las mismas e inversamente proporcional al cuadrado de la distancia que las separa:

$F=K*\frac{q1*q2}{d^{2} }$

donde:

F es la fuerza eléctrica de atracción o repulsión. En el Sistema Internacional (S.I.) se mide en Newtons (N).
q1 y q2 son lo valores de las dos cargas puntuales. En el S.I. se miden en Culombios (C).
d es el valor de la distancia que las separa. En el S.I. se mide en metros (m).
K es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío K tiene un valor aproximadamente de 9*10⁹ $\frac{N*m^{2} }{C^{2} }$ .

En este caso:

F=?

K= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$

q1= -1.6*10⁻¹⁹ C

q2= 1.6*10⁻¹⁹ C

d= 5.3*10⁻¹¹ m

Reemplazando:

$F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{(-1.6*10^{19} C)*(1.6*10^{19} C)}{(5.3*10^{-11} )^{2} }$

Resolviendo:

F= -8.2*10⁻⁸ N

La fuerza eléctrica es -8.2*10⁻⁸ N

6 0

4 years ago

How to solve a torque problem

podryga [215]

you must first select an axis of rotation about which to calculate moment arms and torques.

6 0

3 years ago

Two speakers that are 12.0 m apart produce in-phase sound waves of frequency 245 Hz in a room where the speed of sound is 340 m/

Cerrena [4.2K]

Answer:

a) Please see below as the answer is self-explanatory

b) 0.35 m

c) 0.7 m

Explanation:

a) As there is no difference in the path (because she is exactly at the midpoint between both speakers) that the waves do in order to reach to her ear, she listens both waves with the same intensity.

The same effect would be experimented, if the difference between paths, were an even multiple of the half of the wavelength.

b) In order to have a destructive interference, the difference in path (in the worst case) must be equal to an odd multiple of the half wavelength.

In any wave, there is a fixed relationship between speed, frequency and wavelength, as follows:

λ = v / f

Replacing with our givens for frequency (245 Hz) and v (340 m/s), we have:

λ = 340 m/s / 245 Hz = 1.4 m

The condition for destructive interference, is as follows:

Δd = d₂-d₁ = (2n + 1) *λ/2

For n=0, we have the shortest distance:

Δd = λ/2 = 0.7 m

So, in order to have such a path difference, she must walk exactly the half of this distance from the center, i.e., 0.35 m.

c) With the same reasoning as above, as the condition for constructive interference, as we have already mentioned, is that the path difference be at least one full wavelength, we can say:

Δd = d₂-d₁ = λ

So, in order to have such a path difference, she must walk exactly the half of this distance from the center, i.e., 0.7 m.

4 0

3 years ago

How does water deposit sediment

uysha [10]

Erosion can move sediment through water, ice, or wind. Water can wash sediment, such as gravel or pebbles, down from a creek, into a river, and eventually to that river's delta. Deltas, river banks, and the bottom of waterfalls are common areas where sediment accumulates. i hope this answers your question

3 0

3 years ago