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3 years ago

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If there was a high pressure system in your area and a bunch of clouds were blown in from a different direction, how would the p

ressure system in your area change? Would it change or stay the same

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

Idk but I had to “answer a q”

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The molar solubility of calcium sulfide in a 0.222 M sodium sulfide solution is:________-

timurjin [86]

Sorry I don’t get the question Buh I’m sure you’ll get it eventually

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2 years ago

Copper can be broken into simpler substances so what is it

allochka39001 [22]

Cooper cannot be broken down into a simpler substance since it is an element meaning it had its own atoms.

6 0

2 years ago

Just as one dozen eggs always has 12 eggs in it, one mole of a

zzz [600]

Answer:

$6.022x10^{23}atoms \ Al$

Explanation:

Hello,

In this case, given the described concept regarding the Avogadro's number, we can easily notice that 27.0 g of aluminium foil has 6.022x10²³ atoms as shown below based on the mass-mole-particles relationship:

$27.0gAl*\frac{1molAl}{27.0gAl} *\frac{6.022x10^{23}atoms \ Al}{1molAl} \\\\=6.022x10^{23}atoms \ Al$

Notice this is backed up by the fact that aluminium molar mass if 27.0 g/mol.

Best regards.

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2 years ago

The process that changes a solid directly into a gas is called sublimation. A solid that begins with a mass of 450 g will sublim

cluponka [151]

The mass is conserved, so it stays the same, 450g

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2 years ago

Read 2 more answers

A rock contains 0.623 mg of 206Pb for every 1.000 mg of 238U present. Assuming that no lead was originally present, that all the

maxonik [38]

Answer:

t = 3,496x10⁹ years

Explanation:

The decay of ²³⁸U is:

²³⁸U → ²⁰⁶Pb + 8He + 6e⁻

Moles of ²⁰⁶Pb presents in 0,623mg are:

0,623x10⁻³g×(1mol / 206g) = 3,02x10⁻⁶ moles of ²⁰⁶Pb.

These moles are equals to moles of ²³⁸U before decay, that means, 3,02x10⁻⁶ moles²³⁸U

In grams:

3,02x10⁻⁶ moles²³⁸U× (238g / 1mol) = 7,20x10⁻⁴ g ²³⁸U = 0,720 mg²³⁸U

That means initial ²³⁸U was 1,000mg + 0,720mg =<em> 1,720mg</em>

Applying the formula:

ln (N₀/N) t₁₂ = t ln2

Where N₀ is initial amount of uranium (1,720mg), N is concentration of uranium (1,000mg), half-life time is a constant (t₁₂= 4,468x10⁹ years) and t is the time transcurred for the reaction. Replacing:

ln(1,720/1)*4,468x10⁹ years = t ln2

<em>t = 3,496x10⁹ years</em>

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I hope it helps!

6 0

2 years ago