All categories

4 years ago

NUCLEAR ENERGY ?????????????????????? ?

2 answers:

6 0

It's what I eat in my cereal everyday,Jk

Nuclear energy creates nuclear waste
nuclear energy creates nuclear bombs
their is nuclear energy plants that produce lots of electricity
and too much nuclear energy causes cancer
their is nuclear energy in the air but not enough to hurt you

babymother [125]4 years ago

6 0

Nuclear energy creates nuclear waste

nuclear energy creates nuclear bombs

their is nuclear energy plants that produce lots of electricity

and too much nuclear energy causes cancer

their is nuclear energy in the air but not enough to hurt you

Read more on Brainly.com - brainly.com/question/3215005#readmore

You might be interested in

Newton’s law of cooling states that dx dt = −k(x−A) where x is the temperature,t is time, A is the ambient temperature, and k &g

lys-0071 [83]

Answer:

a) $X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

b)Does not affect the long term.

Explanation:

Given that

$\dfrac{dx}{dt}=-k(x-A)$

A = A0 cos(ωt)

$\dfrac{dx}{dt}=-k(x-A_o cos(\omega t))$

$\dfrac{dx}{dt}+kx=kA_o cos(\omega t)$

This is linear equation so integration factor ,I

$I=e^{\int kdt}$

$I=e^{kt}$

Now by using linear equation property

$e^{kt} X=\int e^{kt} kA_o cos(\omega t) dt +C$

$e^{kt} X= kA_o \dfrac{e^{kt}}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+Ce^{-kt}$

at t= 0

$X(0)=\dfrac{k^2A_o}{\omega^2+k^2}+C$

$X= kA_o\dfrac{1}{k^2+\omega^2}\left ( kcos\omega t+\omega sin\omega t \right )+e^{-kt}\times \left ( X(0)-\dfrac{k^2A_o}{\omega^2+k^2} \right )$

So the initial condition does not affect the long term.

5 0

4 years ago

Whenever one object exerts a force on another object, the second object exerts a force of the same magnitude on the first object

Naddik [55]

Answer:

Explanation:

Newton third law of motion state that action and reaction are equal and opposite

6 0

3 years ago

The discovery of which force most directly impacted our society by allowing the development of nuclear weapons

zhuklara [117]

nuclear ... truman, hiroshima, nagasaki

4 0

3 years ago

A stretched string has a mass per unit length of 5.12 g/cm and a tension of 19.3 N. A sinusoidal wave on this string has an ampl

Sati [7]

Answer:

a. 0.143 mm b. 77.6 rad/m c. 483.18 rad/s d. +1

Explanation:

a. ym

Since the amplitude is 0.143 mm, ym = amplitude = 0.143 mm

b. k

We know k = wave number = 2π/λ where λ = wavelength.

Also, λ = v/f where v = speed of wave in string = √(T/μ) where T = tension in string = 19.3 N and μ = mass per unit length = 5.12 g/cm = 5.12 ÷ 1000 kg/(1 ÷ 100 m) = 0.512 kg/m and f = frequency = 76.9 Hz.

So, λ = v/f = √(T/μ)/f

substituting the values of the variables into the equation, we have

λ = √(T/μ)/f

= √(19.6 N/0.512 kg/m)/76.9 Hz

= √(38.28 Nkg/m)/76.9 Hz

= 6.187 m/s ÷ 76.9 Hz

= 0.081 m

= 81 mm

So, k = 2π/λ

= 2π/0.081 m

= 77.6 rad/m

c. ω

ω = angular frequency = 2πf where f = frequency of wave = 76.9 Hz

So, ω = 2πf

= 2π × 76.9 Hz

= 483.18 rad/s

d. The correct choice of sign in front of ω?

Since the wave is travelling in the negative x - direction, the sign in front of ω is positive. That is +1.

4 0

3 years ago

.In real life, a given system can approach equilibrium from different starting points but will still have the same equilibrium c

Degger [83]

<span>It does not matter where the system starts but it will reach to an equilibrium state when the equilibrium ratio is reached.

hope it helps </span>

5 0

3 years ago