The first requirement is to
look at all the vital information’s given in the question. Based on those
information’s the answer to the question can be easily reached.
Distance that needs to be covered for the race = 38.4 kilometer
Time required to complete the race = 4.5 hours
Then
Average speed = Distance/Time
= 38.4/4.5 km/hour
= 8.53 km/hr
So the average speed would be 8.53 Km/hr.
I hope the answer to the
question is what you were looking for and the procedure is clear to you.
The answer is D) Velocity
In order to answer either of these, we need to know the energy content of coal ... like kwh (or joules or BTU) in each kilogram (or pound or ton) of coal.
Answer:
The magnitude of vector B is 43 units and it points in the negative y-direction.
Explanation:
Resultant of vectors = vector sum of all the vectors
Vector A = 29j
Vector B = ?
Resultant of vector A and B = R = -14j
R = A + B
-14j = 29j + B
B = -14j - 29j = - 43j
Hence, the magnitude of vector B is 43 units and it points in the negative y-direction.
a. The speed of the tsunami at ocean depth of 8000 m is 1,019.66 km/h.
b. The speed of the tsunami at ocean depth of 3500 m is 660.75 km/h.
c. The speed of the tsunami at ocean depth of 70 m is 89.66 km/h.
d. The speed of the tsunami at ocean depth of 5 m is 30.625 km/h.
<h3>
Speed of the tsunami at the given depths</h3>
The speed of the tsunami is calculated from method of extrapolation or interpolation as shown below;
<h3>Speed at 8000 meters</h3>
8000 m -------- ?
7000 m -------- 943 km/h
4000 m -------- 713 km/h
(8000 - 7000)/(7000 - 4000) = (? - 943)/(943 - 713)
0.3333 = (? - 943)/230
230(0.3333) = ? - 943
76.66 = ? - 943
? = 1,019.66 km/h
<h3>Speed at 3500 m</h3>
4000 m ---------- 713 km/h
3500 m ---------- ?
2000 m ----------- 504 km/h
(4000 - 3500)/(4000 - 2000) = (713 - ?) / (713 - 504)
0.25 = (713 - ?) /209
0.25(209) = 713 - ?
52.25 = 713 - ?
? = 660.75 km/h
<h3>Speed at 70 m</h3>
200 m ------ 159 km/h
70 m --------- ?
50 m ------- 79 km/h
(200 - 70)/(200 - 50) = (159 - ?)/(159 - 79)
0.8667 = 159 - ? / 80
80(0.8667) = 159 - ?
69.336 = 159 - ?
? = 89.66 km/h
<h3>Speed at 5 meters</h3>
50 m ------- 79 km/h
10 m --------- 36 km/h
5 m ---------- ?
(50 - 5)/(50 - 10) = (79 - ?)/(79 - 36)
1.125 = 79 - ?/43
43(1.125) = 79 - ?
48.375 = 79 - ?
? = 30.625 km/h
Learn more about speed of tsunami here: brainly.com/question/23136161
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