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kaheart [24]
3 years ago
13

How many times faster can a rider go if they are pedaling an Ultimate HPV bike with a power of 500 W compared to pedaling a road

-racing bike with a power of 500 W?
Physics
1 answer:
PIT_PIT [208]3 years ago
6 0

Answer:

IDK

Explanation:

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Two men are standing on a frictionless ice surface holding opposite ends of a rope. One man (mass = 80 kg) pulls on the rope wit
ankoles [38]

Answer:

The acceleration of man 1 and 2 is 3.125\ m/s^2 and 4.167\ m/s^2.

Explanation:

Mass of man 1, m₁ = 80 kg

Mass of man 2, m₂ = 60 kg

One man pulls on the rope with a force of 250 N.

Let a₁ is acceleration of man 1,

F = m₁a₁

a_1=\dfrac{F}{m_1}\\\\a_1=\dfrac{250}{80}\\\\a_1=3.125\ m/s^2

Let a₂ is acceleration of man 1,

F = m₂a₂

a_2=\dfrac{F}{m_2}\\\\a_2=\dfrac{250}{60}\\\\a_2=4.167\ m/s^2

So, the acceleration of man 1 and 2 is 3.125\ m/s^2 and 4.167\ m/s^2.

7 0
3 years ago
If a car accelerates uniformly from rest to 15 meters
Talja [164]

Answer:

1.125m/s^2

Explanation:

Since acceleration is defined as the rate of change in velocity with respect to time. Mathematically

v^2= u^2+2as

Where a,v,u and s are the acceleration, final velocity, initial velocity and distance respectively.

a = ?

u = 0m/s

v = 15m/s

s = 100m

Substituting the values into the formula above

v^2= u^2+2as

15^2=0^2+2×a×100

225= 0+200a

225= 200a

Divide both sides by 200

225/200 = 200a/200

a= 1.125m/s^2

Hence the acceleration of the car is 1.125m/s^2.

Note that the car accelerated uniformly from rest, that was why the initial velocity was 0m/s

8 0
3 years ago
Read 2 more answers
Can someone help me asap this is due at 2 50
Rom4ik [11]
The data is inadequate
8 0
3 years ago
Plzzz help will give brainlist
zhenek [66]

Answer:

A.

Explanation:

this would make sense but it seems to be more like they both sound different

5 0
3 years ago
Starting from rest, a particle that is confined to move along a straight line is accelerated at a rate of 5.0 m/s2. Which one of
Elanso [62]

Answer:

c) The slope is not constant and increases with increasing time.

Explanation:

The equation for the position of this particle (starting from rest is)

s = at^2/2 = 5t^2/2 = 2.5t^2

We can take derivative of this with respect to time t to get the equation of slope:

s' = (2.5t^2)' = 2*2.5t = 5t

As time t increase, the slope would increases with time as well.

6 0
3 years ago
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