Answer:  
A) 1.55  
B) 1.55
C) 12.92
D) 34.08
E)  57.82
Explanation:  
The free body diagram attached, R is the radius of the wheel  
Block B is lighter than block A so block A will move upward while A downward with the same acceleration. Since no snipping will occur, the wheel rotates in clockwise direction.  
At the centre of the whee, torque due to B is given by  
 
  
Similarly, torque due to A is given by  
 
  
The sum of torque at the pivot is given by  
 
  
Replacing  and
 and  by
 by  and
 and  respectively yields
 respectively yields  
 
  
Substituting  for
 for  in the equation
 in the equation  
  
 
  
 
  
The angular acceleration of the wheel is given by  
  
where a is the linear acceleration  
Substituting  for
 for  into equation
 into equation  
 we obtain
 we obtain  
 
  
Net force on block A is  
 
  
Net force on block B is  
 
  
Where g is acceleration due to gravity  
Substituting  and
 and  for
 for  and
 and  respectively into equation
 respectively into equation  and making a the subject we obtain
 and making a the subject we obtain  
 
  
Since  = 3kg and
 = 3kg and  = 7kg
 = 7kg  
g=9.81 and R=0.12m, I=0.22 
  
Substituting these we obtain  
 
  

Therefore, the linear acceleration of block A is 1.55 
(B)
For block B

Therefore, the acceleration of both blocks A and B are same
1.55 
(C)
The angular acceleration is 

(D)
Tension on left side of cord is calculated using


(E)
Tension on right side of cord is calculated using

