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Lina20 [59]
2 years ago
8

All matter had dimensions. Name any 3 of those dimensions

Physics
2 answers:
diamong [38]2 years ago
8 0
A point of a single dimension, a plane of two, and 3D involving the depth of the third dimension.
Kobotan [32]2 years ago
7 0
A point of a single dimension, a plane of two, and 3D involving the depth of the third dimension.
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How do you find circular motion?​
MatroZZZ [7]

Answer:

Explanation:

By multiplying the rotational frequency with the circumference we can determine the average speed of the object. The circular velocity formula is expressed as, vc = 2 πr / T. Where in, r denotes the radius of the circular orbit. T is time period.

6 0
3 years ago
Read 2 more answers
How will the motion of a falling whirligig compare to that of a falling paper ball?
kicyunya [14]

The motion of a falling whirligig is different to that of a falling paper ball due to spinning.

<h3>Type of motion performed by whirligig and falling paper ball </h3>

The motion of a falling whirligig is different from the motion of a falling paper ball because the paper ball falls on the ground without spinning while on the other hand, the whirligig falls on the ground along with spinning.

The falling whirligig performs two motion i.e. one is falling on the ground and the other is spinning during motion whereas paper ball performs one motion i.e. motion in the air towards the ground so we can conclude that the motion of a falling whirligig is different than of a falling paper ball.

Learn more about motion here: brainly.com/question/453639

4 0
2 years ago
The Z0 boson, discovered in 1985, is the mediator of the weak nuclear force, and it typically decays very quickly. Its average r
Dvinal [7]

Answer:

The lifetime of the particle is  \Delta  t  =  2.6*10^{-25} \ s

Explanation:

From the question we are told that

    The average rest energy is E =  91.19 \ GeV =  91.19GeV  *    \frac{1.60 *10^{-10} J }{1GeV} = 1.46 *10^{-8}J

    The intrinsic width is  \Delta E  =2.5eV  = 2.5GeV   *  \frac{1.60 *10^{-10}J  }{1GeV}  =  4*10^{-10} J

The lifetime is mathematically represented as

     \Delta  t  =  \frac{h}{\Delta E}

Where h is the Planck's constant with a value of  1.055*10^{-34} \ J\cdot s  

substituting values

    \Delta  t  =  \frac{1.055*10^{-34}}{4 *10^{-10}}

     \Delta  t  =  2.6*10^{-25} \ s

6 0
3 years ago
2. As a pendulum swings, its energy is constantly converted between kinetic
Alex

Answer:

at point F

Explanation:

To know the point in which the pendulum has the greatest potential energy you can assume that the zero reference of the gravitational energy (it is mandatory to define it) is at the bottom of the pendulum.

Then, when the pendulum reaches it maximum height in its motion the gravitational potential energy is

U = mgh

m: mass of the pendulum

g: gravitational constant

The greatest value is obtained when the pendulum reaches y=h

Furthermore, at this point the pendulum stops to come back in ts motion and then the speed is zero, and so, the kinetic energy (K=1/mv^2=0).

A) answer, at point F

6 0
3 years ago
Will give brainliest
Ivan

Answer:

i cant see the the pic its glitched post a new one i will help

Explanation:

4 0
3 years ago
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