<span>Falcon 9</span><span>Pegasus</span><span>Proton</span><span><span>Satellite </span><span>Launch </span>Vehicle</span><span>Antares</span><span>Zenit</span><span>Atlas V</span><span>Soyuz</span><span>Ariane 5</span><span>Delta IV</span><span><span>Polar Satellite </span><span>Launch </span>Vehicle</span><span><span>Geosynchronous </span><span>Satellite </span>Launch Vehicle</span><span>Vega</span><span>Rokot</span><span>Angara</span><span>Soyuz-2</span><span>Shavit</span><span>H-IIB</span><span>Dnepr</span><span>Safir</span><span>Falcon 1</span><span><span>Long March </span>4B</span><span><span>Long March </span>2D</span><span>Delta II</span><span>H-II</span><span><span>Long March </span>3C</span><span>Soyuz-U</span><span><span>Long March </span>4C</span><span>Black Arrow</span><span><span>Long March </span>3A</span><span>Naro-1</span><span>Zenit-3SL</span><span>Sputnik</span><span><span>Long March </span>2F</span><span>VLS-1</span><span>Vulcan</span><span><span>Long March </span>2C</span><span>Athena</span><span><span>Long March </span>3B</span><span>Juno I</span><span>N1</span><span>Ariane 6</span><span>Kuaizhou</span><span>Zenit-2</span><span>Simorgh</span><span><span>Long March </span>11</span><span>Strela</span><span>Minotaur-C</span><span>Ariane 1</span><span><span>Augmented </span><span>Satellite </span>Launch Vehicle</span><span>Europa<span>
</span></span>
Answer:
F= 224 N
Explanation:
Given that
mass ,m = 80 kg
Radius ,r= 5 m
speed at the top v= 8 m/s
The force at the top = F
Now by using the Second law of Newton's

Now by putting the values

Take g = 10 m/s²

F= 224 N
Therefore the force exerted by the track at the top position will be 224 N.
Answer:
The final velocity of 18 kg ball is
= 42.09 
Explanation:
Mass of first ball
= 18 kg
Mass of second ball
= 47 kg
Initial velocity of 18 kg ball
= 76 
Initial velocity of 47 kg ball = 0
Final velocity of 18 kg ball
= ??
Final velocity of 18 kg ball is given by the formula
= 
Put all the values in above formula we get
= 2 × 18 × 
= 42.09 
Thus, the final velocity of 18 kg ball is
= 42.09 
Sorry, I’m only in 6th Grade, I don’t know the answer to this question.
To solve this problem we will proceed to define the Period of a stick, then we will define the frequency, which is the inverse of the period. We will compare the change suffered by the new length and replace that value. The Time period of meter stick is

Here,
L = Length
g = Gravity
At the same time the frequency is

Therefore the frequency in Terms of the Period is

If bottom third were cut off then the new length is

Replacing this value at the new frequency we have that,


Finally,
