An object is projected upward from the surface of the earth with an initial speed of 3.7 km/s. find the maximum height it reache
1 answer:
The kinetic energy of the object just after it starts its motion from the Earth surface is
where m is the object mass and
its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
and h is the maximum height reached by the object.
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
where m is the object mass and
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
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Answer:
Explanation:
Given
Length of beam
mass of beam
Two forces of equal intensity acted in the opposite direction, therefore, they create a torque of magnitude
Also, the beam starts rotating about its center
So, the moment of inertia of the beam is
Torque is the product of moment of inertia and angular acceleration
When light travels from a medium with higher refractive index into a medium with lower refractive index, there is a maximum angle (called critical angle) for which all the light is reflected, so there is no refraction.
The value of the critical angle is given by:
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get
The value of the critical angle is given by:
when n1 is the refractive index of the first medium, while n2 is the refractive index of the second medium. In our case, n1=1.33 (the water) and n1=1.00 (the air). Putting numbers in, we get