An object is projected upward from the surface of the earth with an initial speed of 3.7 km/s. find the maximum height it reache
1 answer:
The kinetic energy of the object just after it starts its motion from the Earth surface is
where m is the object mass and
its initial speed.
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
and h is the maximum height reached by the object.
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
where m is the object mass and
When it reaches its maximum height, the object speed is zero and all its kinetic energy converted into gravitational potential energy, which is
where
Since the energy of the object must be conserved, K=U, therefore we can write
and we can solve to find h, the maximum height:
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Answer:
x = 4.32 [m]
Explanation:
We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.
∑F = m*a
where:
F = force = 700 [N]
m = mass = 2030 [kg]
a = acceleration [m/s²]
Now replacing:
Then we can determine the final speed using the principle of conservation of momentum and amount of movement.
where:
m₁ = mass of the car = 2030 [kg]
v₁ = velocity at the initial moment = 0 (the car starts from rest)
Imp₁₋₂ = The impulse or momentum (force by the time)
v₂ = final velocity after the impulse [m/s]
Now using the following equation of kinematics, we can determine the distance traveled.
where:
v₂ = final velocity = 1.72 [m/s]
v₁ = initial velocity = 0
a = acceleration = 0.344 [m/s²]
x = distance [m]