Answer:
2 a) it is less dense than the water
2 b) it is more dense than the water
3 a ping pong ball is hollow and less dense than the water so it quickly bounces up to the surface of the water
Answer: The recoil speed is - 8.9604.
m/s.
Explanation: According to the Third Law of Newton, every action has an oppsite and equal reaction, and the Second Law of Newton, Force=mass·acceleration. Acceleration is a variation in velocity by any given time, so Force = mass·velocity·time.
Combining the two laws, there is : m1·v1 = - m2·v2. This is the Law of Conservation of Momentum.
Substituting and calculating:
v2 = - (
) · v1
v2 = -
· 5.24.![10^{6}](https://tex.z-dn.net/?f=10%5E%7B6%7D)
v2 = - 8.9604.![10^{4}](https://tex.z-dn.net/?f=10%5E%7B4%7D)
The recoil speed of the thorium nucleus is - 8.9604.
m/s.
The density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.
<h3>What is the relationship between acceleration and density?</h3>
For a solid falling through a viscous fluid, the acceleration of the object decreases until it attains terminal velocity.
The acceleration of the body increases with increase in density of the solid.
When density of solid = density of liquid, acceleration a = g
When density of solid = 2 × density of the liquid, acceleration a = g/2.
Therefore, the density of the metal is twice the density of liquid since acceleration, a is half of accelerating due to gravity, g.
Learn more about density and acceleration at: brainly.com/question/1156422
#SPJ1
Answer:
hmm OK is there any news about London is modern enough or
Answer:
- Because the mass is also 6 times greater, so the acceleration is the same.
Explanation:
Force is mass multiplied by acceleration. This is (in one dimension):
![F = m a](https://tex.z-dn.net/?f=F%20%3D%20m%20a)
Now, we can see what acceleration will every rock feel:
Lets call
the force over the first rock, that has a mass
, and lets call
the force over the second rock, that has a mass
. We can write the following equations:
![F_1 = m_1 * a_1](https://tex.z-dn.net/?f=F_1%20%3D%20m_1%20%2A%20a_1)
and
.
We also know that:
, so:
.
But the mass is also six times greater.
![m_2 = 6* m_1](https://tex.z-dn.net/?f=m_2%20%3D%206%2A%20m_1)
so...
.
Now, lets obtain the acceleration. For the first rock we got:
![a_1 = \frac{F_1}{m_1}](https://tex.z-dn.net/?f=a_1%20%3D%20%5Cfrac%7BF_1%7D%7Bm_1%7D)
and for the second rock
![a_2 = \frac{6 * F_1}{ 6 * m_1}](https://tex.z-dn.net/?f=a_2%20%3D%20%5Cfrac%7B6%20%2A%20F_1%7D%7B%206%20%2A%20m_1%7D)
![a_2 = \frac{ F_1}{ m_1}](https://tex.z-dn.net/?f=a_2%20%3D%20%5Cfrac%7B%20F_1%7D%7B%20m_1%7D)
But this is the same acceleration that the first rock has! So, the kinematics will be the same.