A small rock is thrown vertically upward with a speed of 21.0 m/sm/s from the edge of the roof of a 21.0-mm-tall building. The r
1 answer:
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Let the height where we are trapped is H
now to find the time to reach the key at the bottom is given as
now we have
now if the speed of sound is considered to be 340 m/s then time taken by the sound to reach at the top is given as
now the total time is given as
now by solving above equation we have
H = 48 m
now height of one floor is 3 m
so our position must be
Answer:
v = 88.89 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of momentum which tells us that the initial momentum of a body plus the momentum added to that body will be equal to the final momentum of the body.
We must make up the following equation:
where:
F = force applied = 4000 [N]
t = time = 0.001 [s]
m = mass = 0.045 [kg]
v = velocity [m/s]