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Vikki [24]
3 years ago
15

Osmium is one of the densest elements known, what is its density if 2.72 g has a volume of 0.121 cm3?

Chemistry
2 answers:
AnnZ [28]3 years ago
7 0
Mass / volume = density
2.72g/0.121mL = 22.5g/mL

1cm3 = 1mL
kramer3 years ago
3 0

Explanation:

The given data is as follows.

          mass = 2.72 g

          volume = 0.121 cm^{3}

As the density is mass divided by volume.

Mathematically,     Density = \frac{mass}{volume}

Hence, putting the given values into the above formula and calculate the density as follows.

              Density = \frac{mass}{volume}

                           = \frac{2.72 g}{0.121 cm^{3}}

                           = 22.47 g/cm^{3}

Thus, we can conclude that density of osmium is 22.47 g/cm^{3}.

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Stable nuclei with low atomic numbers, up to 20, have a neutron to proton ratio of approximately ________.
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A 35.66g sample of copper is heated using 600j of energy. if the original temperature of the copper is 85C what is its final tem
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This problem is providing the mass, energy, initial temperature and specific heat of a sample of copper that is required to calculate the final temperature.

Thus, we recall the general heat equation:

Q=mC(T_f-T_i)\\

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T_f=T_i+\frac{Q}{mC}

Finally, we plug in the numbers to obtain:

T_f=85\°C+\frac{600J}{35.66g*0.38\frac{J}{g\°C} } \\\\T_f=129.3\°C

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3 years ago
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A 75.0-milliliter lightbulb is filled with neon. There are 7.16 × 10-4 moles of gas in it, and the absolute pressure is 116.8 ki
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Answer:- 1467 K

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We know that, 101.325 kPa = 1 atm

So, 116.8kPa(\frac{1aym}{101.325kPa})

= 1.15 atm

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T = ?

Let's plug in the values in the equation and solve it for T.

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T=\frac{0.08625}{0.00005878}

T = 1467 K

So, the temperature of the light bulb would be 1467 K.

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