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professor190 [17]
3 years ago
5

Turning on a flashlight is what type of energy to what type of energy

Physics
1 answer:
MissTica3 years ago
8 0
Turning on a flashlight uses a battery, right? Chemical energy is stored in that battery. If you use the battery, you're converting that chemical energy to an electrical energy.

In a flashlight then, the electrical energy becomes light energy and thermal energy in the bulb. Why light and thermal? The flashlight gives us light and then, gives out heat. This is why when we touch light bulbs, it feels hot.

I hope you find this answer the most helpful! :)
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A 5.00 kg crate is on a 21.0° hill.
mojhsa [17]

Answer: 4575N

Explanation:

For y component, W = mgcosø

W = 500×9.8cos21

W = 4574.54N

Find the diagram in the attached file

8 0
3 years ago
Write down your definition of work in the space below: ​
skelet666 [1.2K]

Answer:

Work is the energy transferred to or from an object via the application of force along a displacement.

5 0
2 years ago
Read 2 more answers
What is the speaker’s power output if the sound intensity level is 102 dBdB at a distance of 25 mm ? Express your answer to two
lesya [120]

Answer:

Power  = 124.50 W

Explanation:

Given that:

The Sound intensity of a speaker output is 102 dB

and the distance r = 25 m

For the intensity of sound,

\beta (dB)= 10 \  log_{10 } (\dfrac{I}{I_o})

where;

the threshold of hearing   I_o = 10^{-12} (W/m^2)

\dfrac{102 }{10}= log_{10}( \dfrac{I}{10^{-12}})

10^{10.2} =  \dfrac{I}{10^{-12}}

I = 10^{10.2} \times 10^{-12}

I = 0.01585 W/m²

If we recall, we know remember that ;

Power = Intensity × A rea

Power = 0.01585 W/m² × 4 × 3.142 × (25 m)²

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7 0
2 years ago
1. If 800 C of electric charge passed through a light bulb in 4 min; what is the mag
9966 [12]

The electric current passing through the bulb would be 3.3A

<u>Explanation:</u>

Given:

Electric charge, q = 800C

Time, t = 4 min

           = 4 X 60 sec

           = 240 sec

Electric current, I = ?

We know,

Current  = \frac{Charge}{Time}

On substituting the value we get:

I = \frac{800}{4 X 60} \\\\I = 3.3A

Thus, the electric current passing through the bulb would be 3.3A

5 0
2 years ago
2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i
Mekhanik [1.2K]

Answer:

See below

Explanation:

See attached diagram

280 km   east then 190 km north

Use Pythagorean theorem to find the resultant displacement

d^2 = 280^2 + 190^2

d = 338.4 km

Angle will be    arctan ( 190/280) = 34.16 °

4 0
1 year ago
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