Answer:
Equivalent resistanfe in parallel (R):
1/R = 1/100 + 1/200 + 1/300
1/R = (6 + 3 + 2)/600
1/R = 11/600
R = 600/11 = 54.55 ohms
The momentum increases by a factor of 2
Explanation:
We can solve this problem by rewriting the momentum of the rocket in terms of the kinetic energy and the mass.
The kinetic energy of the rocket is:
(1)
where
m is the mass
v is the velocity
The momentum of the rocket is
(2)
From eq.(1) we get
and substituting into (2),
Now in this problem we have:
- The kinetic energy of the rocket is increased by a factor 8:
- The mass is reduced by half:
Substituting, we find the new momentum:
So, the momentum increases by a factor of 2.
Learn more about momentum and kinetic energy:
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Answer:
50m/s, 187.5m
Explanation:
Consider unit analysis:
m/s² = m/(s×s)
This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.
Velocity is being increased per second, and this is called acceleration:
a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1
From the question, we have the variables:
a = 5m/s²
(delta)v = v2 - 25m/s
(delta)t = 5s (initial time is 0)
a = v/t
(5m/s^2)=v/5s
25m/s = v2 - 25m/s
50m/s = v2
The final velocity of the vehicle is 50m/s.
A formula exists to find displacement with regards to acceleration:
d=v(initial) × t +1/2 × a × t²
d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²
d=125m+1/2×125m
d=125m+62.5m
d=187.5m
The distance travelled by the vehicle is 192.5m.
<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>
Answer:
It is easier to stop the bicycle moving at a lower velocity because it will require a <em>smaller force</em> to stop it when compared to a bicycle with a higher velocity that needs a<em> bigger force.</em>
Explanation:
The question above is related to "Newton's Law of Motion." According to the <em>Third Law of Motion</em>, whenever an object exerts a force on another object <em>(action force)</em>, an equal force is exerted against it. This force is of the same magnitude but opposite direction.
When it comes to moving bicycles, the force that stops their movement is called "friction." Applying the law of motion, the higher the speed, the higher the force<em> </em>that is needed to stop it while the lower the speed, the lower the force<em> </em>that is needed to stop it.
