The answer is D. 32 m.
The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:
⇒
It is given:
t = 10 s
d = ?
So:
It would be best to cover the cardiac, smooth, and skeletal muscles! =)
Answer:
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Explanation:
1. If a worker has come into contact with electricity the worker may not be able to remove themselves from the electrical source. The human body is a good conductor of electricity. If you touch a person while they are in contact with the electrical source, the electricity will flow through your body causing electrical shock. Firstly attempt to turn off the source of the electricity (disconnect). If the electrical source can not readily and safely be turned off, use a non-conducting object, such as a fibreglass object or a wooden pole, to remove the person from the electrical source.
2. C- Electrical energy.The term electrical activity means that the food itself has the power to generate electric energy that persists some period of time. This work presents a purely renewable energy as energy comes. the zinc reacts with food tissue.
Answer:
The tension in the rope is 262.88 N
Explanation:
Given:
Weight 
N
Length of rope 
m
Initial speed of ball 
For finding the tension in the rope,
First find the mass of rod,
( 
)
kg
Tension in the rope is,
N
Therefore, the tension in the rope is 262.88 N
Answer:
Explanation:
(ΔK + ΔUg + ΔUs + ΔEch + ΔEth = W)
ΔK is increase in kinetic energy . As the athelete is lifting the barbell at constant speed change in kinetic energy is zero .
ΔK = 0
ΔUg is change in potential energy . It will be positive as weight is being lifted so its potential energy is increasing .
ΔUg = positive
ΔUs is change in the potential energy of sportsperson . It is zero since there is no change in the height of athlete .
ΔUs = 0
ΔEth is change in the energy of earth . Here earth is doing negative work . It is so because it is exerting force downwards and displacement is upwards . Hence it is doing negative work . Hence
ΔEth = negative .
b )
work done by athlete
= 400 x 2 = 800 J
energy output = 800 J
c )
It is 25% of metabolic energy output of his body
so metalic energy output of body
= 4x 800 J .
3200 J
power = energy output / time
= 3200 / 1.6
= 2000 W .
d )
1 ) Since he is doing same amount of work , his metabolic energy output is same as that in earlier case .
2 ) Since he is doing the same exercise in less time so his power is increased . Hence in the second day his power is more .
