All categories

3 years ago

There is a 3-kg toy cart moving at 4 m/s. Calculate the kinetic energy of the cart.

Physics

1 answer:

m_a_m_a [10]3 years ago

5 0

The kinetic energy of the cart is 24 J.

Explanation:

The acceleration of a given mass from rest to the velocity is known as kinetic energy. It gains energy from acceleration and remains in this state until the speed of the object changes.

The kinetic energy is the given by,

K.E = 1/2 mv^2

Given the mass m = 3 kg, v = 4 m / s.

K.E = 1/2 $\times$ 3 $\times$ (4)^2

K.E = 24 J.

You might be interested in

The suns energy reaches the sun by Conduction Convection Radiation Fusion

amid [387]

Answer:

Radiation

Explanation:

The sun energy reaches us by Radiation.

8 0

3 years ago

Read 2 more answers

Sharon the ant (Aaron’s sister) sits at the edge of a turntable of radius R that is spinning with period T. As she makes one-hal

Dmitry_Shevchenko [17]

Answer:

$a = \dfrac{4\pi^2R}{T^2}$

Explanation:

The acceleration of a circular motion is given by

$a = \omega^2 R$

where $\omega$ is the angular velocity and $R$ is the radius.

Angular velocity is related to the period, T, by

$\omega=\dfrac{2\pi}{T}$

Substitute into the previous formula.

$a = (\dfrac{2\pi}{T})^2 R$

$a = \dfrac{4\pi^2R}{T^2}$

This acceleration does not depend on the linear or angular displacement. Hence, the amount of rotation does not change it.

6 0

3 years ago

(a) How much work is required to lift a 35-kg object from the ground 3.0 m into the air? (b) How much gravitational potential en

V125BC [204]

Answer:

(a) work required to lift the object is 1029 J

(b) the gravitational potential energy gained by this object is 1029 J

Explanation:

Given;

mass of the object, m = 35 kg

height through which the object was lifted, h = 3 m

(a) work required to lift the object

W = F x d

W = (mg) x h

W = 35 x 9.8 x 3

W = 1029 J

(b) the gravitational potential energy gained by this object is calculated as;

ΔP.E = Pf - Pi

where;

Pi is the initial gravitational potential energy, at initial height (hi = 0)

ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)

ΔP.E = 1029 J

7 0

3 years ago

An attack helicopter is equipped with a 20- mm cannon that fires 87 g shells in the forward direction with a muzzle speed of 853

uysha [10]

Answer

given,

mass of the shell = 87 g = 0.087 Kg

speed of the muzzle = 853 m/s

mass of the helicopter = 4410 kg

A burst of 176 shell fired in 2.93 s

resulting average force = ?

momentum of the shell = m v

= 0.087 x 853

= 74.21 kgm/s

momentum of 176 shell is = 176 p

= 176 x 74.21

= 13060.96

momentum of helicopter = - 13060.96 kgm/s

amount of speed reduce a = $\dfrac{13060.96}{M}$

a= $\dfrac{13060.96}{4410}$

a = 2.96 m/s²

velocity = \dfrac{2.96}{2.93}

v = 1.01 m/s

5 0

3 years ago

Read 2 more answers

The pressure gauge shown below has a spring for which k = 60 N/m, and the area of the piston is 0.50 cm2. Its right end is conne

kicyunya [14]

Answer:

0.025 m

0.059166 m

Explanation:

P = Pressure

A = Area

x = Compression of spring

Force is given by

$F=PA\\\Rightarrow F=30000\times 0.5\times 10^{-4}\\\Rightarrow F=1.5\ N$

From Hooke's law

$F=kx\\\Rightarrow x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{1.5}{60}\\\Rightarrow x=0.025\ m$

The spring is compressed 0.025 m

In the second case

$F_1=1.5\ N$

$F_2=101000\times 0.5\times 10^{-4}\\\Rightarrow F_2=5.05\ N$

Net force would be

$F=F_2-F_1\\\Rightarrow F=5.05-1.5\\\Rightarrow F=3.55\ N$

Compression would be

$x=\dfrac{F}{k}\\\Rightarrow x=\dfrac{3.55}{60}\\\Rightarrow x=0.059167\ m$

The compression of the spring is 0.059166 m

8 0

3 years ago