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trapecia [35]
3 years ago
7

A consulting firm submitted a bid for a large research project. The firm's management initially felt there was a 50/50 chance of

getting the bid. However, the agency to which the bid was submitted subsequently requested additional information on the bid. Experience indicates that on 75% of the successful bids and 40% of the unsuccessful bids the agency requested additional information. If required, round your answers to two decimal places.1. What is the prior probability of the bid being successful (that is, prior to the request for additional information)?2. What is the conditional probability of a request for additional information given that the bid will ultimately be successful?3. Compute the posterior probability that the bid will be successful given a request for additional information (to 2 decimals).
Engineering
1 answer:
klemol [59]3 years ago
6 0

Answer:

1. 0.50

2. 0.75

3. 0.65

Explanation:

1. For the bid being successful with a 50-50 chance, we have the probability:

50/(50 + 50) = 50 / 100 = 0.50

2. Given the request for additional info:

Probability = probability of request and successful / probability of successful

= 75 / 100 = 0.75

3. We will evaluate the probability of being successful given its request

We will use the Bayesian theorem

= [P(request | successful) * P(successful)] / [P(request | successful) * P(successful) + P(request | unsuccessful) * P(unsuccessful)]

= ( 0.75 * 0.5) / (0.75 * 0.5 + 0.4 * 0.5)

= 0.65

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2. A F-22 Raptor has just climbed through an altitude of 9,874 m at 1,567 kph when a disk
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The pressure difference across the sensor housing will be "95 kPa".

According to the question, the values are:

Altitude,

  • 9874

Speed,

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Pressure,

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The temperature will be:

→ T = 15.04-[0.00649(9874)]

→     = 15.04-64.082

→     = -49.042^{\circ} C

now,

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Determine the following parameters for the water having quality x=0.7 at 200 kPa:
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Solution :

Given :

Water have quality x = 0.7 (dryness fraction) at around pressure of 200 kPa

The phase diagram is provided below.

a). The phase is a standard mixture.

b). At pressure, p = 200 kPa, T = $T_{saturated}$

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c). Specific volume

  $v_{f}= 0.001061, \ \ v_g=0.88578 \ m^3/kg$

  $v_x=v_f+x(v_g-v_f)$

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    $u_f=504.5 \ kJ/kg, \ \ u_{fg}=2024.6 \ kJ/kg$

   $u_x=504.5 + 0.7(2024.6)$

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e). Specific enthalpy $(h_x)$

   At $h_f = 504.71, \ \ h_{fg} = 2201.6$

   h_x=504.71+(0.7\times 2201.6)

        $= 2045.83 \ kJ/kg$

f). Enthalpy at m = 0.5 kg

  $H=mh_x$

       $= 0.5 \times 2045.83$

       = 1022.91 kJ

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