Part (a): 1- Since the resistors are in series, therefore, the total resistance is the summation of the two resistors. Therefore: Rtotal = R1 + R2 = 3.11 + 6.15 = 9.26 ohm
2- Since the two resistors are in series, therefore, the current flowing in both is the same. We will use ohm's law to get the current as follows: V = I*R V is the voltage of the battery = 24 v I is the current we want to get R is the total resistance = 9.26 ohm Therefore: 24 = 9.26*I I = 24 / 9.26 I = 2.59 ampere
Part (b): To get the voltage across the second resistor, we will again use Ohm's law as follows: V = I*R V is the voltage we want to get I is the current in the second resistor = 2.59 ampere R is the value of the second resistor = 6.15 ohm Therefore: V = I*R V = 2.59 * 6.15 V = 15.9285 volts