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olya-2409 [2.1K]
2 years ago
6

A world class sprinter can accelerate at 5.0 m/s squared, from the rest in the starting blocks to their top speed in 4.0 seconds

. What distance will such a sprinter cover during that time?
Physics
1 answer:
Airida [17]2 years ago
4 0

Answer:

The distance covered by the sprinter, s = 40 m

Explanation:

Given data,  

The initial velocity of the sprinter, u = 0 m/s

The acceleration of the sprinter, a = 5 m/s²

The time period of acceleration of the sprinter, t = 4 s

Using the II equations of motion

                   s = ut + ½ at²

                       = 0 + ½ (5) (4)²

                       = 40 m

Hence, the distance covered by the sprinter, s = 40 m                    

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An apparatus similar to the one used in lab uses an oscillating motor at one end to vibrate a long rope with frequency f = 40 Hz
Mice21 [21]

Answer:

The displacement in t = 0,  

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y (t) = A* sin ( w * t - φ )

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5 0
3 years ago
A world-class sprinter can burst out of the blocks to essentially top speed (of about 11.5 m/s) in the first 15.0 m of the race.
wolverine [178]
Given:
u = 0, initial speed (sprinter starts from rest)
v = 11.5 m/s, final speed
s = 15 m, distance traveled to attain final speed.

Let
a =  average acceleration,
t = time taken to attain final speed.

Then
v² = u² + 2as
or
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v = u +a t
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(11.5 m/s) = (4.408 m/s²)*(t s)
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Answer:
The average acceleration is 4.41 m/s² (nearest hundredth).
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8 0
3 years ago
Is AG on the periodic table
Taya2010 [7]
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8 0
3 years ago
How could you increase the amount of kenitic energy
Fiesta28 [93]

Answer:

As You know kinetic Energy is equal (mv^2)/2

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Explanation:

8 0
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