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3 years ago

One Newton equals .225

Physics

1 answer:

padilas [110]3 years ago

3 0

The answer to your question is 10.24

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Draw a simple picture of your foot kicking a

Anton [14]

The force is going which ever way the person kicks the ball.

8 0

3 years ago

You are driving at the speed of 27.7 m/s (61.9764 mph) when suddenly the car in front of you (previously traveling at the same s

densk [106]

Here when car in front of us applied brakes then it is slowing down due to frictional force on it

So here we can say that friction force on the car front of our car is given as

$F_f = \mu m g$

So the acceleration of car due to friction is given as

$F_{net} = - \mu mg$

$a = \frac{F_{net}}{m}$

$a = -\mu g$

now it is given that

$\mu = 0.868$

$g = 9.81 m/s^2$

so here we have

$a = -0.868 * 9.81$

$a = -8.52 m/s^2$

so the car will accelerate due to brakes by a = - 8.52 m/s^2

4 0

4 years ago

What is different about the different parts of the electromagnetic spectrum

Archy [21]

Answer:

Each part of the spectrum has a different range of wavelengths (which correspond to frequency, color, and energy) at which you can find it.

4 0

4 years ago

In a position time graph, a curved line represents: acceleration no movement constant velocity

Mumz [18]

Answer:

acceleration or a deceleration

Explanation:

The gradient of a position - time graph represent the velocity.

a straight line indicate a constant velocity (gradient ≠ 0)

when it is a parallel line to the time axis , it indicated no movement

when it is a curved line it indicates a changing velocity (either acceleration or a deceleration) as mentioned in the graph

4 0

3 years ago

When you connect an unknown resistor across the terminals of a 1.50 V D-cell battery having negligible internal resistance, you

g100num [7]

Answer:

Explanation:

Using ohm's law

a) V = IR where V is voltage in Volt, I is current in Ampere and R is resistance in ohms

R = V / I = 1.50 V/ ( 2.05 /1000) A = 731.71 ohms

b) Power = IV = $\frac{V}{R}$ × v = $\frac{V^{2} }{R}$ = $\frac{9^{2} }{731.71}$ = 0.1107 W

c) E = IR + Ir = ( 731.71 × 0.0036) + ( 35 × 0.0036) = 2.76 V

d) Power use by the resistor = I²R = 0.0036² × 731.71 = 0.00948 W = 0.00948 W = 0.000009483 kw × ( 18 / 60 ) H = 2.84 × 10⁻⁶ KW-H

5 0

3 years ago