Answer:
The current on the water layer = 1.64×10^-3A
Explanation:
Let's assume that the radius given for the string originates from the centre of the string. The equation for determining the current in the water layer is given by:
I = V × pi[(Rwater + Rstring)^2 - (Rstring)^2/ ( Resitivity × L)
I =[ 166×10^6 ×3.142[(0.519×10^-4) + (2.15×10^-3])^2 - ( 2.15×10^-3)^2] / ( 183 × 831)
I =[ 521572000(4.848×10^6)- 4.623×10^-6]/ 154566
I = 252.83 -(4.623×10^-6)/ 154566
I = 252.83/154566
I = 1.64× 10^-3A
Answer:
1.196 m
Explanation:
Given the wave equation :
y= 0.05 cos(5.25x-1775t)
Recall the general traverse wave relation :
y(x, t) = Acos(kx - wt)
A = Amplitude
To Obtian the wavelength ;
We compare the both equations :
Take the value of k ;
kx = 5.25x
k = 5.25
Recall;
k = 2π/λ
5.25 = 2π/λ
5.25λ = 2π
λ = 2π / 5.25
λ = (2 * 3.14) / 5.25 = 1.196 m
Explanation:
Relative density=density of liquid÷density of water
1.25=x ÷ 1000
x=1.25 × 1000
x=1250kgm^-3
The functions of the cytoskeleton and the cell wall are similar because they both act like a barrier for the cell.
B). Some elements found in nature exist as molecules.
That is, their atoms travel around in bound pairs.
Examples are Hydrogen, Oxygen, and Nitrogen.
A). No. Without atoms, you can't make a molecule.
C). No. A compound is a chemical combination of two or more elements.
D). No. An atom is the smallest unit of ONE single element.