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3 years ago

5

An 85 kg object is moving at a constant speed of 15 m/s in a circular path,which has a radius of 20 meters. What centripetal for

ce is exterted on the body?

1 answer:

vova2212 [387]3 years ago

7 0

As always,. F = M A. Centripetal acceleration = V-squared / R. So F=M V-squared/R. =. 85 x 225 / 20. = 956.25 Newton's (about 215 pounds). That's the force required to keep that mass moving at that speed around that circle. If the force is less, or not there, then the 85 kg moves slower, or leaves that path.

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Find the interest. A 105-day note for $14,200 at 8.5% interest.

mr Goodwill [35]

<h3><u>Answer</u>;</h3>

$347.22

<h3><u>Explanation</u>;</h3>

Principal = $14,200

Rate = 8.5%

Time = 105 days = 105/365

Interest = Principal x Rate x Time

Interest = 14,200 x 0.085 x 105/365

Interest = 347.219

= $347.22

7 0

4 years ago

The vector values are 4.0 km due East and 3.0 km due north the resultant vector is 5.0 km long and 37 north of East this values

klemol [59]

Answer:

This values shows a right angle triangle

Explanation:

Given;

a vector 4.0 km due East

a 3.0 km due north

the resultant vector is 5.0 km

The resultant vector can be obtained by Pythagoras theorem if the vectors form a right angle triangle.

R² = 4² + 3²

R² = 16 + 9

R² = 25

R = √25

R = 5 km (right angle triangle proved)

Therefore, this values shows a right angle triangle

4 0

3 years ago

When the Glen Canyon hydroelectric power plant in Arizona is running at capacity, 690 m3 of water flows through the dam each sec

igomit [66]

Answer:

The maximum electric power output is $P_{max} =1.339*10^{9} \ W$

Explanation:

From the question we are told that

The capacity of the hydroelectric plant is $\frac{V}{t} = 690 \ m^3 /s$

The level at which water is been released is $h = 220 \ m$

The efficiency is $\eta =$ 0.90

The electric power output is mathematically represented as

$P = \frac{PE_l - PE _o}{t}$

Where $PE_l$ is the potential energy at level h which is mathematically evaluated as

$PE_l = mgh$

and $PE_o$ is the potential energy at ground level which is mathematically evaluated as

$PE_o = mg(0)$

$PE_o = 0$

So

$P = \frac{mgh}{t}$

here $m = V * \rho$

where V is volume and $\rho$ is density of water whose value is $\rho = 1000 kg/m^3$

So

$P = \frac{(\rho * V) * gh}{t}$

$P = \frac{V}{t} * gh \rho$

substituting values

$P =690 * 9.8 * 220 * 1000$

$P =1.488*10^{9} \ W$

The maximum possible electric power output is

$P_{max} = P * \eta$

substituting values

$P_{max} =1.488*10^{9} * 0.90$

$P_{max} =1.339*10^{9} \ W$

6 0

3 years ago

(6) A 75 kg human total footprint area is 0.05 m2 when wearing winter boots. Suppose that you want to walk on snow that can at m

fredd [130]

Answer:

0.25m²

Explanation:

We know that the summation of forces in the vertical direction is zero

So

PA-mg=0

A=mg/p

So

Substituting

A= 75* 9.8/3*10^-3

=0.25m² which is the total shoe area

3 0

3 years ago

Pls help me with this problem!!

Olenka [21]

Answer:

v = 19.6 m/s.

Explanation:

Given that,

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The time period of the ball, T = 1.6s

We need to find the ball's tangential velocity.

The formula for the tangential velocity is given by :

$v=\dfrac{2\pi r}{T}$

Putting all the values in the above formula

$v=\dfrac{2\pi \times 5}{1.6}\\\\v=19.6\ m/s$

So, the tangential velocity of the ball is 19.6 m/s. Hence, the correct option is (c).

7 0

3 years ago