Question

A person applies an impulse of 5.0 kg∙m/s to a box in order to set it in motion. If the person is in contact with the box for 0.25 s, what is the average force exerted by the person on the box?

Answer 1

Answer:

F = 20 N

Explanation:

given,

Impulse, I = 5 Kg.m/s

time of contact, t = 0.25 s

Average force = ?

we know force is equal to change of momentum per unit time.

impulse is equal to change in momentum.

$F = \dfrac{dP}{dt}$

$F = \dfrac{I}{t}$

$F = \dfrac{5}{0.25}$

F = 20 N

The average force exerted by the person on the box is equal to F = 20 N