Answer:
The work done is W = 38J.
Explanation:
We have a force verctor F=(10,18,-6) and two points P(2,3,0) and Q(4,9,15).
The position verctors of these points are P=(2,3,0) and Q=(4,9,15).
The vector that goes from P to Q will be:
R=Q-P=(2,6,15)
Now, considering that the force is constant and travels in the straight line represented by R, the work done will be:
W = F×R = (10,18,-6)×(2,6,15) = 10·2 + 18·6 + (-6)·15 = 38Nm = 38J
∴ W = 38J.
