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Zigmanuir [339]
3 years ago
15

Consulting your data table, choose the date that the Moon is closest to the Descending Ecliptic. Note that the Descending Node i

s defined by a decreasing Ecliptic Latitude as the Moon crosses the Ecliptic.
Physics
1 answer:
Alenkinab [10]3 years ago
6 0
Found the choices that accompanied this question.

The date that the Moon is closest to the Descending Ecliptic based on the data table is JANUARY 1, 2017.

The date that the Moon is closest to the Ascending Ecliptic based on the data table is JANUARY 16, 2017.

 The Ecliptic Longitude oF the Moon when it is nearest<span>to the descending node is 322 degrees.</span>
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Answer:

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How many significant digits are measurement 0.00210 mg?
jek_recluse [69]
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3 years ago
Read 2 more answers
A ball is thrown into the air with a vertical velocity of 50 m/s and a horizontal
daser333 [38]

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Projectile Motion.

Since, here given that, vertical velocity= 50m/s

we know that u*sin(theta) = vertical velocity

so the time taken to reach the maximum height or the time of Ascent is equal to

T = Usin(theta) ÷ g, here g = 9.8 m/s^2

so we get as,

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5 0
2 years ago
How much energy will a stock tank heater rated at 1790 Watts use in a 24 hour period? 1. 1790 × 24 × 3600 Joules 2. 1790 × 24 ×
Rashid [163]
<h2>Option 1 is the correct answer.</h2>

Explanation:

Power of heater, P = 1790 W

Time used, t = 24 hours = 24 x 60 x 60 = 24 x 3600 s

We have the equation

               \texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}

We need to find energy,

Substituting

                 \texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}\\\\1790=\frac{\texttt{Energy}}{24\times 3600}

                  Energy = 1790 x 24 x 3600 J

Option 1 is the correct answer.

3 0
2 years ago
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