Answer:
19m
Explanation:
we have proper length L = 100m
the speed of the train v = 0.95
the speed of light is given as = 3x10⁸
length of the tunnel is given as = 50 meters
we can solve for the lenght contraction as
LX√1-v²/c²
= 100 * √1-(0.95*3x10⁸)²/(3x10⁸ )
= 31.22 metres
the train would be well seen at
50 - 31.22
= 18.78
= this is approximately 19 metres
we conclude tht the trains ends clears the ends of the tunnel by 19 meters.
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Answer:
The speed of the ball at this distance is 9.15 m/s
Explanation:
Given;
initial speed of the baseball, U = 5.0 m/s.
distance traveled along the path way, h = 3 m
final speed of the baseball at this distance, V = ?
The baseball is falling under the influence of gravity.
Acceleration due to gravity, g is positive, since the baseball is falling towards its direction.
g = 9.8 m/s²
Apply the third kinematic equation;
V² = U² + 2gh
V² = 5² + 2 x 9.8 x 3
V² = 25 + 58.8
V² = 83.8
V = √83.8
V = 9.15 m/s
Therefore, the speed of the ball at this distance is 9.15 m/s
Explanation:
According to Thermal Expansion of solids:
Answer:
In vector form , if angle between velocity vector and acceleration vector is less than 90° and greater than 0° then it is positive acceleration and if it is less than 180° and greater than 90° then it is negative acceleration. If there is no acceleration vector then it is called zero acceleration
Explanation:
