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3 years ago

Step 3 - Fillin the missing numbers: 21 -3 -10 24 b d

Physics

2 answers:

Studentka2010 [4]3 years ago

7 0

Answer:

b = 2

c = -1

d = -2

Complete the division. The remainder is 0.

The quotient is A. x2 - x - 12

Explanation:

on edg.... Good Luck!!!

mash [69]3 years ago

4 0

Answer:

b = 2

c = -1

d = -2

Explanation:

Got this question right on edge

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Blood contains positive and negative ions and therefore is aconductor. A blood vessel, therefore, can be viewed as anelectrical

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Answer:

<h2>Magnetic field required for the given induced EMF is 1.41 T</h2>

Explanation:

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$d = 4.80 mm$

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now we have

$1 \times 10^{-3} = (14.8 \times 10^{-2})B(4.80 \times 10^{-3})$

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3 years ago

A monochromatic light passes through a narrow slit and forms a diffraction pattern on a screen behind the slit. As the wavelengt

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3 years ago

An object of mass m = 5.0 kg hangs from a cord around a light pulley: The length of the cord between the oscillator and the pull

puteri [66]

Answer:

$\mu=0.0049Kg/m$

Explanation:

When a standing wave is formed with six loops means the normal mode of the wave is n=6, the frequency of the normal mode is given by the expression:

$f_n=\frac{nv}{2L}$

Where $L$ is the length of the string and $v$ the velocity of propagation. Use this expression to find the value of $v$ .

$f_6=\frac{6v}{2L}\\(150)=\frac{6v}{2(2)} \\150=\frac{3v}{2} \\3v=150(2)\\ v=\frac{300}{3} \\v=100m/s$

The velocity of propagation is given by the expression:

$v=\sqrt{\frac{T}{\mu }$

Where $\mu$ is the desirable variable of the problem, the linear mass density, and $T$ is the tension of the cord. The tension is equal to the weight of the mass hanging from the cord:

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With the value of the tension and the velocity you can find the mass density:

$v=\sqrt{\frac{T}{\mu}$

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3 years ago

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Answer:

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3 years ago

A 77.0 kg woman slides down a 42.6 m long waterslide inclined at 42.3. at the bottom, she is moving 20.3 m/s.how much work did f

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Answer:

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3 years ago