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Nataliya [291]
3 years ago
7

Large hydrocarbons have what characteristics?

Chemistry
1 answer:
QveST [7]3 years ago
5 0
The answer is D because large hydrocarbons have a higher number of carbon which means an increase in boiling point and also rate of flow decreases, so they become solids.
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Water, H2O, is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to shared __________
adell [148]

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

<h3>What kinds of bonds exist?</h3>
  • Covalent bonds: These are formed between nonmetals and electrons by sharing electrons.
  • Ionic bonds: These are formed between metals, which lose electrons, and nonmetals, which gain electrons.
  • Metallic bonds: There are formed between metals. Electrons are delocalized in a cloud.

Water, H₂O, is a molecule made of 2 nonmetals: oxygen and hydrogen. The bonds that hold water molecules together are due to shared electrons, and known as covalent bonds.

Oxygen and hydrogen share electrons in the molecule of water to form covalent bonds.

Learn more about chemical bonds here: brainly.com/question/6071754

5 0
2 years ago
what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
2 years ago
Wind power is:
12345 [234]
Answer) All of the above
7 0
3 years ago
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The N2O4−NO2 reversible reaction is found to have the following equilibrium partial pressures at 100∘C. Calculate Kp for the rea
timofeeve [1]

Answer:

K_{p} for the reaction is 18.05

Explanation:

Equilibrium constant in terms of partial pressure (K_{p}) for this reaction can be written as-

                K_{p}=\frac{P_{NO_{2}}^{2}}{P_{N_{2}O_{4}}}

where P_{NO_{2}} and P_{N_{2}O_{4}} are equilibrium partial pressure of NO_{2} and N_{2}O_{4} respectively

Hence K_{p}=\frac{(0.095)^{2}}{(0.0005)} = 18.05

So, K_{p} for the reaction is 18.05

3 0
3 years ago
Idenatify the pair in which the formula does not match the name
MissTica
What're the options?

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3 years ago
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