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Tema [17]
4 years ago
11

ball is dropped from rest and hits the ground 1.1 seconds later. What height was the ball released from? ​

Physics
1 answer:
Aleonysh [2.5K]4 years ago
5 0
Height = 1/2 * 9.8 * (1.1^2)
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The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i
sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

F_{net}=T-mg

Now, from Newton's second law, net force equals mass times acceleration.

F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)

Plug in the given values and solve for 'T'. This gives,

T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N

Therefore, the tension in the cable is 19387.5 N.

3 0
4 years ago
What is the acceleration of a 3 kg rock that is thrown with a force of 18 N?
Ket [755]

Answer:6m/s^2

Explanation:

Mass =3kg

Force=18N

Acceleration =force ➗ mass

Acceleration =18 ➗ 3

Acceleration =6

Acceleration =6m/s^2

7 0
4 years ago
10. A kicked soccer ball has an initial velocity of 30 m/s at an angle of 42° above the horizontal, level
Serhud [2]

Answer:

ZAMN

Explanation:

5 0
3 years ago
PLEASE HELP ASAP!!! NO LINKS! Which type of wave does the illustration depict?
Xelga [282]

Answer:

Transverse wave

Explanation:

The wave is moving forwards from the hand to the point of attachment

3 0
3 years ago
A dolphin accelerates at -1.77 m/s2 for
Zepler [3.9K]

Answer:

-19.4 m

Explanation:

Given:

a = -1.77 m/s²

t = 3.33 s

v = -8.77 m/s

Find: Δx

Δx = vt − ½ at²

Δx = (-8.77 m/s) (3.33 s) − ½ (-1.77 m/s²) (3.33 s)²

Δx = -19.4 m

5 0
4 years ago
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