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timama [110]
3 years ago
12

Prefix version of 6600 volts​

Engineering
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

6.6 kilo volts = 6.6 k volts

Explanation:

A prefix is a word, number or a letter that is added before another word. In physics we have different prefixes for the exponential powers of 10, that are placed before units in place of those powers. Some examples are:

deci (d)   ------  10⁻¹

centi (c)   ------  10⁻²

milli (m)   ------   10⁻³

kilo (k)     ------   10³

mega (M) -----   10⁶

giga (G)   ------   10⁹

We have:

6600 volts

converting to exponential form:

=> 6.6 x 10³ volts

Thus, we know that the prefix of kilo (k) is used for 10³.

Hence,

=> <u>6.6 kilo volts = 6.6 k volts</u>

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Each cout statement has a syntax error. Type the first cout statement, and press Run to observe the error message. Fix the error
saul85 [17]

Answer:

1. cout << "Num: " << songNum << endl;

2. cout << songNum << endl;

3. cout << songNum <<" songs" << endl;

Explanation:

//Full Code

#include <iostream>

using namespace std;

int main ()

{

int songNum;

songNum = 5;

cout << "Num: " << songNum << endl;

cout << songNum << endl;

cout << songNum <<" songs" << endl;

return 0;

}

1. The error in the first cout statement is that variable songnum is not declared.

C++ is a case sensitive programme language; it treats upper case and lower case characters differently.

Variable songNum was declared; not songnum.

2. Cout us used to print a Variable that has already been declared.

The error arises in int songNum in the second cout statement.

3. When printing more than one variables or values, they must be separated with <<

4 0
3 years ago
Problem Statement: Air flows at a rate of 0.1 kg/s through a device as shown below. The pressure and temperature of the air at l
Tema [17]

Answer:

The answer is "+9.05 kw"

Explanation:

In the given question some information is missing which can be given in the following attachment.

The solution to this question can be defined as follows:

let assume that flow is from 1 to 2 then

Q= 1kw

m=0.1 kg/s

From the steady flow energy equation is:

m\{n_1+ \frac{v^2_1}{z}+ gz_1 \}+Q= m \{h_2+ \frac{v^2_2}{2}+ gz_2\}+w\\\\\ change \ energy\\\\0.1[1.005 \times 800]-1= 0.01[1.005\times 700]+w\\\\w= +9.05 \ kw\\\\

If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.

8 0
3 years ago
Let r be a bank's interest rate in percent per year (APR). An initial amount of money P, also called as principal, will mature t
Liono4ka [1.6K]

Answer:

See explanation below.

Explanation:

For this case the program needs to take the inputs as P,r and n and the output would be as A and printed on the system. The code is:

# Inputs

P = float(input("Enter the present value : "))  

r = float(input("Enter your APR : "))  

n = float(input("Enter the number of years : ") )

# Output

A = P*(1 +(r/100))**n

print("The future values is:", A)  

And the result obtained is:

Enter the present value : 1000

Enter your APR : 0.95

Enter the number of years : 5

The future values is: 1048.4111145526908

7 0
3 years ago
What is chemical engineering​
viktelen [127]

Answer:

Chemical engineering is the branch of engineering that deals with chemical production and the manufacture of products through chemical processes

Explanation:

8 0
4 years ago
The weatherman states that the current temperature is 95 F and the dew point is 74 F. What is the current relative humidity?
spayn [35]

Answer:

Current Relative Humidity is 29.623

Given:

Current Temperature, T_{c} = 95 F = 35^{\circ}C

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Solution:

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where

a = 17.625

b = 237.7

Now, using the above formula and given values:

23.34 = (237.7\frac{\frac{17.625\times 35}{ 237.7 + 35} + lnRH}{17.625 - \frac{17.625\times 35}{237.7 + 35} + lnRH})

23.34(17.625 - 2.26 + lnRH) = (237.7\times 2.26 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

358.62 + 23.34lnRH) = (537.20 + lnRH)

On solving the above eqn, we get:

RH = 29.623

3 0
3 years ago
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