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vovikov84 [41]
3 years ago
10

An LC circuit consists of a 3.400 capacitor and a coil with self-inductance 0.080 H and no appreciable resistance. At t = 0 the

capacitor is fully charged so the potential between the plates is 1.588 V and the current in the inductor is zero. What is the charge on the plates? How long after t = 0 will the current in the circuit be maximum? What will be the maximum current? What is the total energy in the system?
Physics
1 answer:
Gnoma [55]3 years ago
7 0

Answer:

Explanation:

charge on the capacitor = capacitance x potential

= 1.588 x 3.4

= 5.4 C  

Energy of capacitor  = 1 / 2 C V ² , C is capacitance , V is potential

=  .5 x 3.4 x 1.588²

= 4.29  J

If I be maximum current

energy of inductor = 1/2 L I² , L is inductance of inductor .

energy of inductance = Energy of capacitor

1/2 L I² = 4.29

I² = 107.25

I = 10.35 A

Time period of oscillation

T = 2π √ LC

=2π √ .08 X 3.4

= 3.275 s

current in the inductor will be maximum in T / 4 time

= 3.275 / 4

= .819 s.

Total energy of the system

= initial energy of the capacitor

=  4.29  J

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The correct answer is zero.

The answer is zero because the inductor acts as open circuit.

i= i_0[1-e^{-\frac{t}{\tau} }]

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A pulley with a radius of 3.0 cm and a rotational inertia of 4.5 x 10–3 kg∙m2 is suspended from the ceiling. A rope passes over
vekshin1

Answer:

22J

Explanation:

Given :

radius 'r'= 3cm

rotational inertia 'I'=4.5 x 10^{-3} kgm²

mass on one side of rope 'm_{1'= 2kg

mass on other side of rope'm_{2' =4kg

velocity'v' of mass m_{2' = 2m/s

Angular velocity of the pulley is given by

‎ω = v /r => 2/ 3x 10^{-2

‎ω = 66.67 rad/s

For the rotating body, we have

KE = \frac{1}{2} I ω²

KE_p = \frac{1}{2} (4.5 *10^{-3} )(66.67^{2} )

KE_p = 10J

Next is to calculate kinetic energy of the blocks :

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