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bixtya [17]
3 years ago
7

Ax = 44.4 m and Ay = 25.1 m Find the magnitude of the vector.

Physics
1 answer:
max2010maxim [7]3 years ago
6 0

Answer:

The magnitude of the vector A is <u>51 m.</u>

Explanation:

Given:

The horizontal component of a vector A is given as:

A_x=44.4\ m

The vertical component of a vector A is given as:

A_y=25.1\ m

Now, we know that, a vector A can be resolved into two mutually perpendicular components; one along the x axis and the other along the y axis. The magnitude of the vector A can be written as the square root of the sum of the squares of each component.

Therefore, the magnitude of vector A is given as:

|\overrightarrow A|=\sqrt{A_{x}^2+A_{y}^2}

Now, plug in 44.4 for A_x, 25.1 for A_y and solve for the magnitude of A. This gives,

|\overrightarrow A|=\sqrt{(44.4)^2+(25.1)^2}\\|\overrightarrow A|=\sqrt{1971.36+630.01}\\|\overrightarrow A|=\sqrt{2601.37}\\|\overrightarrow A|=51\ m

Therefore, the magnitude of the vector A is 51 m.

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