If A is the measurement in the x-axis and B is the direction in the y-direction,
Magnitude = √(1.5² + (-3)²)
Magnitude = 3.35 units
Direction:
tan∅ = y/x
tan∅ = 3/1.5
∅ = 63.4°
Tan is negative in the second and fourth quadrants, and the values of x and y indicate that it is in the fourth quadrant. Therefore, the direction is 63.4° below the positive x-axis.
Answer:
80 Meters.
Explanation:
What I did was took how many seconds the ball traveled and multiply how fast the ball was going. I actually do a lot of these questions. :))
May I please have brainlyest??
If you are trying to loosen a stubborn bolt from a piece of metal with a wrench and fail, should you find a wrench for which the handle is: longer.
<h3>What is angular acceleration?</h3>
- The temporal rate at which angular velocity changes is known as angular acceleration. The standard unit of measurement is radians per second per second. Therefore, = d d t. Rotational acceleration is another name for angular acceleration.
- Angular velocity divided by acceleration time can be used to define angular acceleration. (t). As an alternative, use pi times the drive speed (n) divided by the acceleration time (t) times 30. Radians per second squared (Rad/sec2) is the standard SI unit for rotational acceleration resulting from this equation.
- To calculate angular velocity, we can use one of three formulas. The definition itself provides the first. Theta = position angle, t = time, and w = angular velocity, where w = angular velocity, theta = position angle, and t = time. Angular velocity is the rate of change of an object's position angle with respect to time.
- The symbol for angular acceleration is, and it is measured in rad/s2, or radians per second square.
If you are trying to loosen a stubborn bolt from a piece of metal with a wrench and fail, should you find a wrench for which the handle is: longer.
To learn more about angular acceleration, refer to:
brainly.com/question/20912191
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The maximum possible value for d is <u>33.4 m</u>.
The bear chases the tourist with a speed v₁ and the tourist runs with a speed v₂. The distance between the tourist and the car is d and the distance between the tourist and the bear is 22 m. for the tourist to reach the car safely, he should cover the distance d in the same time as the bear, which covers a distance d+22 m.
Therefore,
Substitute 3.8m/s for v₂ and 6.3 m/s for v₁. Solve for d.
The maximum distance between the tourist and his car, for him to be safe from the chasing bear is <u>33.4 m.</u>
I'm sorry but I don't really understand the question. What is the quest actually asking???
