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Dimas [21]
3 years ago
8

The synthesization of new carbon compounds is studied in ____ chemistry?

Chemistry
1 answer:
oee [108]3 years ago
8 0

Answer: Organic

Explanation:

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PLEASE HELP ME !!!!!!!
love history [14]

Answer:

it would be 5,045

Explanation:

because it is closer to 5,000. pls correct me if wrong

5 0
2 years ago
A 40.04 g sample of a protein contains 17.16 g of carbon, 3.17 g of hydrogen, 13.71 g of oxygen, and the rest being nitrogen. Th
Arturiano [62]

Answer:

ffgghhhhhgffffffcvvvvvvvvvvvvvvvvvv

Explanation:

cccvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv

8 0
2 years ago
Match the term (Endothermic) with the correct definition
Darya [45]

Answer:

energy goes into the chemical and cool downs the surrounding area.

5 0
2 years ago
In a similar experiment, unlabeled 4-butanolide was allowed to stand in an acidic solution in which the water had been labeled w
Lina20 [59]

Answer:

Please see attachment

Explanation:

Please see attachment

6 0
3 years ago
What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
3 years ago
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