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Zepler [3.9K]
3 years ago
14

Draw a complete Lewis structure for the conjugate acid of nitromethane that shows all bonds, unshared electron pairs, and minimi

zed formal charges, where appropriate.

Chemistry
2 answers:
nydimaria [60]3 years ago
7 0

Answer:

Lewis structures are shown below

Explanation:

  • In Lewis structure of nitromethane, a negative charge is present on oxygen atom in nitro group.
  • Hence this oxygen atom acts as a basic center preferably.
  • Therefore conjugate acid of nitromethane should be drawn by adding a hydrogen atom with this oxygen atom.
  • Lewis structure of nitromethane as well as it's conjugate acid has been shown below including all the lone pairs and formal charges

Dvinal [7]3 years ago
5 0
 <span>CH3-N=O, [with one more O attached to N] <=====> CH2=N-O- + H+ ; this negative charge on O can be with the other O too, thus it gets stabilises itself.This is called the conjugate acid, as it has lost a proton. This is called Nitro- Acinitroso tautomerism .


I hope my answers has come to your help. God bless and have a nice day ahead!</span>
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Explanation:

Data

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Process

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                      CxHyOz  + O₂ ⇒   CO₂  +  H₂O

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                      44 g of CO₂ --------------  12 g of C

                      3.268 g of CO₂  --------    x

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                        x = 0.891 g of Carbon

                       12 g of carbon -----------  1 mol

                       0.891 g of C     ----------   x

                       x = (0.891 x 1) / 12

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2.- Calculate the moles and mass of hydrogen

                      18 g of water --------------- 2 g of H

                      1.672 g of H₂O ------------  x

                      x = (1.672 x 2) / 18

                      x = 0.186 g of hydrogen

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                      0.186 g of H       ------------  x

                      x = (0.186 x 1) / 1

                      x = 0.186 moles of H

3.- Calculate the mass of Oxygen and its moles

Mass of Oxygen = 1.376 - 0.891 - 0.186

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Moles of Oxygen

                             16 g of Oxygen ---------------- 1 mol

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                             x = (0.299 x 1) / 16

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4.- Divide by the lowest number of moles

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Hydrogen     0.186/ 0.019 = 9.7 = 10

Oxygen         0.019/ 0.019 = 1

5.- Write the empirical formula

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