It is (A) for the first one and (B) for the second one.
Answer:
Speed, Vfx = 7.619 m/s
Explanation:
Vertical distance, Dx = 5.4m
Horizontal distance, Dy = 8m
Acceleration due to gravity, g = 9.8m/s²
Initial speed, Vix = 0m/s²
To find the speed, we would use the second equation of motion to find the time, t;
Dx = Vixt + ½gt²
Substituting into the equation, we have;
5.4 = 0(t) + ½(9.8)*t²
5.4 = 0 + 4.9t²
Rearranging the equation, we have;
4.9t² = 5.4
t² = 5.4/4.9
t² = 1.1020
Taking the square root of both sides;
t = 1.050 secs.
For the speed;
Dy = Vfxt
Vfx = Dy/t
Vfx = 8/1.050
Vfx = 7.619 m/s
<em>Therefore, the speed of the pelican is 7.619 m/s</em>
Answer:
The thrust of the jet engine is 4188.81 N.
Explanation:
Given that,
Speed = 260 m/s
Rate in air= 53.3 kg/s
Rate of fuel = 3.63 kg/s
Relative speed = 317 m/s
We need to calculate the rate of mass change in the rocket
Using formula of rate of mass

Put the value into the formula


We need to calculate the thrust of the jet engine
Using formula of thrust

Put the value into the formula


Hence, The thrust of the jet engine is 4188.81 N.
Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student