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yKpoI14uk [10]
3 years ago
7

What is true about a circular orbit?

Physics
1 answer:
Sliva [168]3 years ago
8 0
-- The speed of the orbiting body is the same at every point in its orbit.

-- Since a circle is the ellipse with coincident foci, the central body is
at the center of the circular orbit.

-- The radius of the circular orbit drawn from the central body to the
orbiting body sweeps out the same amount of area in every same
amount of time.

-- The forces of attraction between the central body and the orbiting body
may be electrostatic, magnetic, or gravitational.

-- The circular orbit never occurs in nature.  In the case of TV satellites
that appear 'fixed' in the sky, their orbits must constantly be adjusted to
maintain circularity and prevent them from drifting off station..
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Which section (A or B) of the roller coaster shows positive acceleration?
Step2247 [10]

It is (A) for the first one and (B) for the second one.

6 0
4 years ago
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A pelican flying along a horizontal path drops a fish from a height of 5.4 m. The fish travels 8.0 m horizontally before it hits
umka2103 [35]

Answer:

Speed, Vfx = 7.619 m/s

Explanation:

Vertical distance, Dx = 5.4m

Horizontal distance, Dy = 8m

Acceleration due to gravity, g = 9.8m/s²

Initial speed, Vix = 0m/s²

To find the speed, we would use the second equation of motion to find the time, t;

Dx = Vixt + ½gt²

Substituting into the equation, we have;

5.4 = 0(t) + ½(9.8)*t²

5.4 =  0 + 4.9t²

Rearranging the equation, we have;

4.9t² = 5.4

t² = 5.4/4.9

t² = 1.1020

Taking the square root of both sides;

t = 1.050 secs.

For the speed;

Dy = Vfxt

Vfx = Dy/t

Vfx = 8/1.050

Vfx = 7.619 m/s

<em>Therefore, the speed of the pelican is 7.619 m/s</em>

6 0
3 years ago
A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a
IrinaVladis [17]

Answer:

The thrust of the jet engine is 4188.81 N.

Explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

\dfrac{dM}{dt}=\dfrac{dM_{a}}{dt}+\dfrac{dM_{f}}{dt}

Put the value into the formula

\dfrac{dM}{dt}=53.3+3.63

\dfrac{dM}{dt}=56.93\ kg/s

We need to calculate the thrust of the jet engine

Using formula of thrust

T=\dfrac{dM}{dt}u-\dfrac{dM_{a}}{dt}v

Put the value into the formula

T=56.93\times317-53.3\times260

T=4188.81\ N

Hence, The thrust of the jet engine is 4188.81 N.

7 0
4 years ago
When multiple light waves overlap and cause patterns of bright and dark areas it is called wave ?
dmitriy555 [2]

Answer: Interference

Explanation:

3 0
4 years ago
Mike stands on a scale in an elevator. If the elevator is accelerating upwards with 4.9 m/s2, the scale reading is ____ times Mi
Bas_tet [7]

Answer:

F - M a      force exerted by scales on student

M a = M (9.8 + 4.9) m/s^2      upwards chosen as positive

a = 1.5 g        net acceleration of student  due to force of scales

W =M g       weight of student   (actual weight)

Wapp = M 1.5 * g      apparent weight (on scales) of student

7 0
3 years ago
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