Suppose you are sitting on a rotating stool holding a 2 kgmass
1 answer:
Answer:Increase
Explanation:
Given
You are holding 2 kg mass in each outstreched hand
If the masses are dropped then Moment of inertia will decease by
Where m=2 kg
r=length of stretched arm
Since angular momentum is conserved therefore decrease in Moment of inertia will result in increase of angular velocity
as I=constant
I=Moment of inertia
=angular velocity
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Answer:
<em>k = 25.18 N/m</em>
Explanation:
<u>Simple Harmonic Oscillator</u>
It consists of a weight attached to one end of a spring being allowed to move forth and back.
If m is the mass of the weight and k is the constant of the spring, the period of the oscillation is given by:
If the period is known, we can find the value of the constant by solving for k:
Substituting the given values m=5 Kg and T=2.8 seconds:
k = 25.18 N/m