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3 years ago

Suppose you are sitting on a rotating stool holding a 2 kgmass

Physics

1 answer:

Aloiza [94]3 years ago

3 0

Answer:Increase

Explanation:

Given

You are holding 2 kg mass in each outstreched hand

If the masses are dropped then Moment of inertia will decease by $2mr^2$

Where m=2 kg

r=length of stretched arm

Since angular momentum is conserved therefore decrease in Moment of inertia will result in increase of angular velocity

as I $\omega$ =constant

I=Moment of inertia

$\omega$ =angular velocity

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Georgia [21]

The Doppler Effect...

<span>It describes an increase (or decrease) in the frequency of sound, light, or other waves as the source and observer move toward (or away from) each other.</span>

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3 years ago

Read 2 more answers

An advertising balloon shaped like a giant soda can is 15 feet tall and 7 feet wide. How many cubic feet of helium will be neede

Iteru [2.4K]

Answer:

576.975 cubic feet of helium will be needed to fully inflate the balloon

Explanation:

To determine how many cubic feet of helium will be needed to fully inflate the balloon, we will determine the volume of the balloon.

From the question,

The balloon is shaped like a giant soda can.

A giant soda can is cylindrical.

Hence, we can determine the volume of the balloon shaped like a giant soda can by using the formula for finding the volume of a cylinder.

The formula for finding the volume of a cylinder is

V = πr²h

Where V is the volume of the cylinder

π is a constant (Take π = 3.14)

r is the radius of the cylinder

and h is the height of the cylinder

From the question, the balloon is 15 feet tall and 7 feet wide

Hence,

Height, h = 15 feet

Width = 7 feet

(NOTE: The width of a cylinder is the same as the diameter)

Then, diameter = 7 feet

Radius, r is given by

Radius = Diameter / 2

Then, Radius = 7 feet / 2 = 3.5 feet

∴ Radius, r = 3.5 feet

Now, for the volume of the balloon,

V = πr²h

V = 3.14 × (3.5)² × 15

V = 3.14 × 12.25 × 15

V = 576.975 cubic feet

This is the volume of the balloon.

Hence, 576.975 cubic feet of helium will be needed to fully inflate the balloon.

5 0

3 years ago

Very large accelerations can injure the body, especially if they last for a considerable length of time. The severity index (SI)

Ludmilka [50]

Answer:

a) The severity index (SI) is 3047.749, b) The injured travels 0.345 meters during the collision.

Explanation:

a) The g-multiple of the acceleration, that is, a ratio of the person's acceleration to gravitational acceleration, is:

$a' = \frac{35\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$a' = 3.569$

The time taken for the injured to accelerate to final speed is given by this formula under the assumption of constant acceleration:

$v_{f} = v_{o} + a \cdot t$

Where:

$v_{o}$ - Initial speed, measured in meters per second.

$v_{f}$ - Final speed, measured in meter per second.

$a$ - Acceleration, measured in $\frac{m}{s^{2}}$ .

$t$ - Time, measured in seconds.

$t = \frac{v_{f}-v_{o}}{a}$

$t = \frac{\left(12\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s} \right)}{35\,\frac{m}{s^{2}} }$

$t = 0.095\,s$

Lastly, the severity index is now determined:

$SI = \frac{a'^{5}}{2\cdot t}$

$SI = \frac{3.569^{5}}{2\cdot (0.095\,s)}$

$SI = 3047.749$

b) The initial and final speed of the injured are $1.944\,\frac{m}{s}$ and $5.278\,\frac{m}{s}$ , respectively. The travelled distance can be determined from this equation of motion:

$v_{f}^{2} = v_{o}^{2} + 2\cdot a \cdot \Delta s$

Where $\Delta s$ is the travelled distance, measured in meters.

$\Delta s = \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}$

$\Delta s = \frac{\left(5.278\,\frac{m}{s} \right)^{2}-\left(1.944\,\frac{m}{s} \right)^{2}}{2\cdot \left(35\,\frac{m}{s^{2}} \right)}$

$\Delta s = 0.345\,m$ .

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3 years ago

What is the law of gravity?

Harlamova29_29 [7]

Newton's law of universal gravitation states that a particle attracts every other particle in the universe using a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them

7 0

3 years ago

There are 5510 lines per centimeter in a grating that is used with light whose wavelegth is 467 nm. A flat observation screen is

Mademuasel [1]

Answer:

1.696 nm

Explanation:

For a diffraction grating, dsinθ = mλ where d = number of lines per metre of grating = 5510 lines per cm = 551000 lines per metre and λ = wavelength of light = 467 nm = 467 × 10⁻⁹ m. For a principal maximum, m = 1. So,

dsinθ = mλ = (1)λ = λ

dsinθ = λ

sinθ = λ/d.

Also tanθ = w/D where w = distance of center of screen to principal maximum and D = distance of grating to screen = 1.03 m

From trig ratios 1 + cot²θ = cosec²θ

1 + (1/tan²θ) = 1/(sin²θ)

substituting the values of sinθ and tanθ we have

1 + (D/w)² = (d/λ)²

(D/w)² = (d/λ)² - 1

(w/D)² = 1/[(d/λ)² - 1]

(w/D) = 1/√[(d/λ)² - 1]

w = D/√[(d/λ)² - 1] = 1.03 m/√[(551000/467 × 10⁻⁹ )² - 1] = 1.03 m/√[(1179.87 × 10⁹ )² - 1] = 1.03 m/1179.87 × 10⁹ = 0.000848 × 10⁻⁹ = 0.848 × 10⁻¹² m = 0.848 nm.

w is also the distance from the center to the other principal maximum on the other side.

So for both principal maxima to be on the screen, its minimum width must be 2w = 2 × 0.848 nm = 1.696 nm

So, the minimum width of the screen must be 1.696 nm

4 0

3 years ago