Elements of Group 1 and group 2 in the periodic
table contain elements so reactive that they are never found in the free state
<u>Explanation</u>:
The metals in group 1 of periodic table consisting of 'alkali metals' which include lithium, potassium, sodium, rubidium, Francium and caesium. They are highly reactive because they have low ionisation energy and larger radius. The group 2 metals consist of 'alkaline earth metals' which include calcium, strontium, barium, beryllium, radium and magnesium. These alkaline earth metal have +2 oxidation number, hence are highly reactive.
These both group metals are mostly reactive and so are never found in a free state. When they are exposed to air they would immediately react with oxygen. Hence, are stored in oils to avoid oxidation.
Answer:
Explanation:
chemical bonds between atoms are formed or broken.
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The formula of acetic acid is CH3COOH => C2H4O2.
So, the acetic acid has the same number of atoms of carbon (C) than of oxygen (O).
Therefore, the sample that contains 96.5 moles of carbon, will contain also 96.5 moles of O.
Answer: 96.5 moles of oxygen.
Answer is although the question should have 3 significant figures.
<h3>What is
significant figures?</h3>
Fe + CuSO4 --> Cu + FeSO4
It is already balanced
1 mol Fe : 1 mol CuSO4 : 1 mol Cu : 1 mol FeSO4
- atomic masses of Fe and Cu
Fe: 55.8 g/mol
Cu: 63.5 g/mol
number of moles = mass in grams / atomic mass = 93.7 g / 55.8 g/mol = 1.679 mol
1 mol Fe / 1 mol Cu => 1.679 mol Fe / 1.679 mole Cu
- mass of Cu in 1.679 moles Cu
mass = atomic mass * number of atoms = 63.5 g/mol * 1.679 moles = 106.6 g = 107 rounded to 3 significant figures.
To learn more about significant figures, refer to:
brainly.com/question/24491627
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Ga2(CO3)3 is the formula.