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Scrat [10]
3 years ago
6

What does internal combustion engines release?

Chemistry
2 answers:
In-s [12.5K]3 years ago
6 0
Internal combustion engines release exhaust
Pavlova-9 [17]3 years ago
4 0

Answer:

you should give options.

Explanation:

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Consider a reaction that has a positive ΔH and a positive ΔS. Which of the following statements is TRUE?A) This reaction will be
Alja [10]

Answer: A) This reaction will be spontaneous only at high temperatures

Explanation:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Using Gibbs Helmholtz equation:

\Delta G=\Delta H-T\Delta S

Given : \Delta H=+ve

\Delta S=+ve

\Delta G=(+ve)-T(+ve)

\Delta G=(+ve)(-ve)

Thus the value of  \Delta G  is negative and spontaneous when temperature is high.

4 0
3 years ago
In chemistry, what is the definition of the term salt? a compound consisting of an anion from an acid and a cation from a base a
inysia [295]
In chemistry<span>, a </span>salt<span> is an ionic compound that can be formed by the neutralization reaction of an acid and a base.So yes it is</span>
7 0
3 years ago
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Xxxx only girls can join gca-vtki-tqh ​
4vir4ik [10]

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it is the app for homework not for nonsense things.

do good be good and see good and think good

6 0
2 years ago
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When a 1.00 L sample of water from the surface of the Dead Sea (which is more than 400 meters below sea level and much saltier t
Harlamova29_29 [7]

Answer: Molarity of MgCl_2 in the original sample was 1.96M

Explanation:

Molarity is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{\text{no of moles}}{\text{Volume in L}}

{\text {moles of solute}=\frac{\text {given mass}}{\text {molar mass}}=\frac{186g}{95g/mol}=1.96

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.96}{1.00L}

Molarity=1.96mol/L

Thus molarity of MgCl_2 in the original sample was 1.96M

4 0
3 years ago
An industrial manufacturer wants to convert 175 kg of methane into HCN. Calculate the masses of ammonia and molecular oxygen req
Tema [17]
Given:

175 kilograms of Methane (CH4) to be synthesized into Hydrogen Cyanide (HCN)

The balanced chemical equation is shown below:

2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To calculate for the masses of ammonia and oxygen needed, our basis will be 175 kg CH4.

Molar mass:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol

mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol 
mass of NH3 = 185.94 kg NH3 needed

mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
mass of O2 = 525 kg

mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
mass of O = 131.25 kg O 
4 0
3 years ago
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