A stone is thrown vertically upward with velocity 9.8ms 1)calculate the time taken to reach maximum height.2)what is the maximum

Question

3 years ago

10

height reached 3) what is time taken to reach ground 4)what velocity it reaches the ground

2 answers:

agasfer [191] · Answer 1 · 2022-01-22T04:32:36+03:00

6 0

Answer:

It would take 6 seconds before hitting the ground

Explanation:

ira [324] · Answer 2 · 2022-01-22T02:03:27+03:00

Answer:

1.t=-1.96sec

2.H=4.8m

3.T=1.96sec

4.R=19.2m

Explanation:

u=9.8,t=?,sin theta=1

using formula t=2usintheta/g

t=2x9.8x1=19.6/10

t=1.96seconds

using formula H=u(squared)sin(squared)theta/2g

H=9.8(squared)x1(squared)/2x10

H=96x1/20

H=96/20

H=4.8m

using formula T=2usintheta/g

T=2x9.8x1/10

T=19.6/10

T=1.96sec

using the formula R=u(squared)sin2theta/g

R=9.8(squared)x2/10

R=96x2/10

R=192.08/10

R=19.2