Answer:
0.83 J of work
Explanation:
2 J of work is required to stretch a spring from 34cm to 46cm
So that is 12cm stretched with 2 J of work
We can make that 6cm for 1 J of work
So, we need the find the work for stretching 36cm to 41cm
Which is 5cm
So, What is the work required to stretch 5cm?
1 J of work for 6cm
x work for 5cm
So, by proportion method
1 : 6 :: x : 5
6 * x = 1 * 5
6x = 5
x = 5/6
= 0.83
So to stretch 36cm to 41cm we need 0.83 J of work
Force = mass x acceleration
113N = 25.2a
a = 4.48 m/s^2
Vf = Vi + at
Vf = 2.33 + 4.48(2) = 11.3 m/s
The efficiency of the process is 42%
From the question given above, the following data were obtained:
Useful energy = 250 watt
Wasteful energy = 600 watt
<h3>Efficiency =? </h3>
The efficiency of the process can be obtained as illustrated below:

<h3>Efficiency = 42%</h3>
Therefore, the efficiency of the process is 42%
Learn more: brainly.com/question/2300041
Answer:
three times the original diameter
Explanation:
From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:

Here, d is the wire's diameter,
is the electrical resistivity of the material and R is the resistance of the wire. We have 
