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larisa86 [58]
3 years ago
14

What is the pitch circle diameter of a 50-tooth spur gear having a circular pitch of 0.375 inch

Engineering
1 answer:
Dmitrij [34]3 years ago
4 0

Answer:

Pitch circle diameter = 5,66 inch

Explanation:

<u>According to the pitch circle diameter formula</u>

      <em>Dc= Dp - 2b</em> ; where Dp= primitive diameter, b= dedendum of the tooth and also the dedendum formula is b= 1,25 Pc/π.

     The definition of primitive diameter is equal to (Pc*Z)/π ; Pc= circular pitch and Z= number of teeths.

    <u>Replacing in the formula </u>

        ⇒ Dc= (Pc*Z)/π - 2* 1,25 Pc/π,    Pc= 0,375 ; Z=50

  In conclusion the pitch circle diameter is equal to:

            Dc= 5,66 inch.      

   

         

<h3>           </h3>

 

   

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3 years ago
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3 years ago
A transformer winding contains 900 turns of wire which creates 400 ohms of primary importance how many terms of the same size wi
Eduardwww [97]

Answer: 255

255 turns are required to create 25 ohms of  secondary impedance.

Explanation:

Given that,

Number of turns in primary wire N₁ = 900

impedance on Primary wire Z₁ = 400 ohms

Number of turns in Secondary wire N₂ = ?

impedance on Secondary wire Z₂ = 25 ohms

we know that, the relationship between turn and impedance is

Zp / Zs = ( Np / Ns )²

(Primary impedance / secondary impedance) = Number of turns in primary wire / Number of turns in secondary wire)²

there fore

Z₁ / Z₂ = ( N₁ / N₂ )²

Now we substitute

( 400 / 25 ) = ( 900 / N₂ )²

400 / 25 = 900² / N₂²

we cross multiple to get our N₂

400 × N₂² =  900² × 25

N₂² = ( 900² × 25 ) / 400

N₂² = ( 810000 × 25 ) / 400

N₂² = 20250000 / 400

N₂² = 50625

N₂ = √50625

N₂ = 225

Therefore 255 turns are required to create 25 ohms of  secondary impedance.

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