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tatuchka [14]
2 years ago
14

In a "Rotor-ride" at a carnival, people rotate in a vertical cylindrically walled "room." If the room radius is 5.5 m, and the r

otation frequency 0.5 revolutions per second (rps) when the floor drops out, what minimum coefficient of friction keeps the people from slipping down? What type of friction is this? People on this ride said they were "pressed against the wall," however what is really happening? 0.18
Physics
1 answer:
Crank2 years ago
6 0

Answer:

0.181

Explanation:

We can convert the 0.5 rps into standard angular velocity unit rad/s knowing that each revolution is 2π:

ω = 0.5 rps = 0.5*2π = 3.14 rad/s

From here we can calculate the centripetal acceleration

a_c = \omega^2r = 3.14^2*5.5 = 54.3 m/s^2

Using Newton 2nd law we can calculate the centripetal force that pressing on the rider, as well as the reactive normal force:

F = N = a_cm = 54.3 m

Also the friction force and friction acceleration

F_f = N\mu = 54.3 m \mu N

a_f = F_f / m = 54.3 \mu

For the rider to not slide down, friction acceleration must win over gravitational acceleration g = 9.81 m/s2:

g = a_f = 54.3 \mu

9.81 = 54.3 \mu

\mu = 9.81 / 54.3 = 0.181

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Komok [63]

Given: The number = 0.0069 that has to be expressed in scientific notation

Concept: When we express any number in scientific notation then we shall consider two points.

(i) If we shift the decimal point from left to right after first (non-zero) digit then we count the number of shifted place of decimal and write them in terms of the negative power of 10. For example,  0.004789 = 4.789 ×10⁻³

(ii) If we shift the decimal point from right to left after first (non-zero) digit from the left end then we count the number of shifted place and write then in terms of the positive power of 10. For example,  4789.24 = 4.78924 ×10⁺³ = 4.78924 ×10³ Now, we shall convert the given number 0.0069 in scientific notation

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5 0
3 years ago
sonic is sliding down a frictionless 15m tall hill. He starts at the top with a velocity of 10m/s. At the bottom of the hill he
podryga [215]

Answer:

The maximum speed of sonic at the bottom of the hill is equal to 19.85m/s and the spring constant of the spring is equal to (497.4xmass of sonic) N/m

Energy approach has been used to sole the problem.

The points of interest for the analysis of the problem are point 1 the top of the hill and point 2 the bottom of the hill just before hitting the spring

The maximum velocity of sonic is independent of the his mass or the geometry. It is only depends on the vertical distance involved

Explanation:

The step by step solution to the problem can be found in the attachment below. The principle of energy conservation has been applied to solve the problem. This means that if energy disappears in one form it will appear in another.

As in this problem, the potential and kinetic energy at the top of the hill were converted to only kinetic energy at the bottom of the hill. This kinetic energy too got converted into elastic potential energy .

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Explanation:

(a)   Formula to calculate the density is as follows.

            \rho = \frac{Q}{\frac{4}{3}\pi a^{3}}

                       = \frac{6.50 \times 10^{-6}}{\frac{4}{3} \times 3.14 \times (0.04)^{3}}

                     = 2.42 \times 10^{-2} C/m^{3}

Now, calculate the charge as follows.

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(b)  For r = 6.50 cm, the value of charge will be calculated as follows.

                q_{in} = \frac{Q}{\frac{4}{3}\pi a^{3}}

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                          = 7.454 \mu C

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Answer: equal

Explanation:

Don’t know why honestly

5 0
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