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2 years ago

True or false: Relative to the shoreline, a boat always moves in the direction in which it is pointing.

Physics

1 answer:

Alja [10]2 years ago

3 0

Answer:

False

Explanation:

A boat can go reverse like a car

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NEES HELP!!!!

OLga [1]

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

6 0

1 year ago

A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to

salantis [7]

Answer:

Explanation:

They drove 30km north. The displacement adds up to 25km therefore making the distance greater

Hope this helps!

6 0

2 years ago

A solid conducting sphere with radius R carries a positive total charge Q. The sphere is surrounded by an insulating shell with

Illusion [34]

Answer:

Explanation:

Volume of the insulating shell is,

$V_{shell}=\frac{4}{3}\pi(R^3_2-R^3_1)$

Charge density of the shell is,

$\rho=\frac{Q_{shell}}{\frac{4}{3}\pi(R^3_2-R^3_1)}$

Here, $R_2 =2R, R_1 =R \,and\, Q_{shell} =-Q$

$\rho=\frac{Q_{shell}}{\frac{4}{3}\pi((2R)^3-R^3)}=\frac{-3Q}{28\piR^3}$

The electric field is $E=\frac{1}{4\pi\epsilon_0}\frac{Qr}{R^3}$

For 0 <r<R the electric field is zero, because the electric field inside the conductor is zero.

For R <r <2R According to gauss law

$E(4\pi r^2)=\frac{Q}{\epsilon_0}+\frac{4\pi\rho}{3\epsilon_0}(r^3-R^3)$

substitute $\rho=\frac{-3Q}{28\piR^3}$

$E=\frac{2}{7\pi\epsilon_0}\frac{Q}{r^2}-\frac{Qr}{28\piR^3}$

The net charge enclosed for each r in this range is positive and the electric field is outward

For r>2R

Charge enclosed is zero, so electric field is zero

8 0

2 years ago

which layer of the atmosphere is directly above the troposphere A. exosphere B. mesosphere C. troposphere or D. stratosphere

lozanna [386]

The layer above it would be D. the Stratosphere

8 0

2 years ago

Read 2 more answers

An engine does 10 J of work and exhausts 25 J of waste heat during each cycle.

noname [10]

The thermal efficiency is defined as follows

$\eta = 1 - \frac{Q_{\text{out}}}{Q_\text{in}}$ ,

and the energy which is put into the system is

$Q_{\text{in}} = W_\text{out} + Q_\text{out}$ .

In your case $Q_\text{in} = 25 \text{ J},W_\text{out}=10 \text{ J}.$

So $Q_\text{out}=10 \text{ J}$ which gives an efficiency of

$\eta = 1 - \frac{10 \text{ J}}{25 \text { J}} = 0.6 = 60 \%$ .

4 0

2 years ago