3 years ago

Help awnser physics

Physics

1 answer:

kirill115 [55]3 years ago

3 0

Answer:

there I think the answer is measuring tape we cannot use a metre rule because it measures straight lines and I think measuring tape is better because it is flexible thus makes measurement easier

You might be interested in

4: Which of the following is true of an object in a circular motion at a constant speed?

Andre45 [30]

Yes it could. And IT IS !

7 0

2 years ago

A pen contains a spring with a spring constant of 257 N/m. When the tip of the pen is in its retracted position, the spring is c

Mandarinka [93]

Explanation:

Below is an attachment containing the solution.

3 0

3 years ago

A spectroscope prism separates the white light from a star into a very wide spectrum. When widely spread, black lines appear in

topjm [15]

Answer:

C. It helps scientists detect dark matter.

Explanation:

I got a 100% on my test. hope it help and I hope your having an awesome day :)

5 0

2 years ago

Read 2 more answers

The area of the velocity time graph gives displacement of the body true or false?

mote1985 [20]

The area of the velocity time graph gives displacement of the body true or false?

The answer this is true.

8 0

2 years ago

Read 2 more answers

Consider the hydrogen atom. How does the energy difference between adjacent orbit radii change as the principal quantum number i

Kisachek [45]

Answer:

the energy difference between adjacent levels decreases as the quantum number increases

Explanation:

The energy levels of the hydrogen atom are given by the following formula:

$E=-E_0 \frac{1}{n^2}$

where

$E_0 = 13.6 eV$ is a constant

n is the level number

We can write therefore the energy difference between adjacent levels as

$\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})$

We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is

$\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV$

While the difference between the levels n=2 and n=3 is

$\Delta E=-13.6 eV(\frac{1}{2^2}-\frac{1}{3^2})=-13.6 eV(\frac{1}{4}-\frac{1}{9})=-13.6 eV(\frac{5}{36})=-1.9 eV$

And so on.

So, the energy difference between adjacent levels decreases as the quantum number increases.

5 0

3 years ago

Help awnser physics​

Help awnser physics