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3 years ago

What substance is acting as the Brønsted-Lowry base in the forward reaction below?

1 answer:

3 0

The question is asking to state the substance that is acting as the Bronsted Lowry base in the forward reaction, base on my research, I would say that the substance acting to said formulas is the NH3. I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarification

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What is a rise in seawater levels pushed to shore during a hurricane called?

zalisa [80]

Answer:

A storm surge

Explanation:

A rise in sea level that happens during tropical cyclones, and storms like typhoons or hurricanes is called a Storm Surge.

5 0

4 years ago

Limonene is a nonpolar molecule. The water molecules around it form Select one: a. covalent bonds with limonene and entropy incr

pickupchik [31]

Answer:C. Hydrogen Bonds with themselves and entropy decreases.

Explanation:Limonene is a chiral aliphatic Hydrocarbon liquid that is relatively stable as MONOTERPENE which cracks at high temperature to produce ISOPRENE. D-limonene is produced from CITRUS FRUIT through CENTRIFUGAL SEPARATION AND STEAM DISTILLATION. The most widely used conversion of limonene is to CARVONE.

The water molecules around LIMONENE forms Hydrogen Bonds with themselves and entropy of the reaction decreases,the name Limonene was obtained from the PEEL OF LEMON.

6 0

4 years ago

The sum of the first 10 terms of an arithmetic progression is 120 and the sum of first twenty is 840. find sum of first 30 terms

STatiana [176]

Answer:

The sum of first 30 terms of the arithmetic progression is 2160.

Explanation:

For an arithmetic progression, the sum of first $n$ terms with first term as $a$ and common difference $d$ is given as:

$S_n=\frac{n}{2}(2a+(n-1)d)$

Now, it is given that:

$For\ n=10,S_n=120\\For\ n=20,S_n=840$

Now, plug in these values and frame two equations in $a\ and\ d$

$S_{10}=\frac{10}{2}(2a+(10-1)d)\\120=5(2a+9d)\\2a+9d=\frac{120}{5}\\2a+9d=24------------1$

$S_{20}=\frac{20}{2}(2a+(20-1)d)\\840=10(2a+19d)\\2a+19d=\frac{840}{10}\\2a+19d=84-----------2$

Now, we solve equations (1) and (2) for $a\ and\ d$ . Subtract equation (1) from equation (2). This gives,

$2a+19d-2a-9d=84-24\\19d-9d=60\\10d=60\\d=\frac{60}{10}=6$

Now, plug in the value of $d=6$ in equation (1) and solve for $a$ .

$2a+9(6)=24\\2a+54=24\\2a=24-54\\2a=-30\\a=\frac{-30}{2}=-15$

Plug in the values of $a=-15,\ n=30\ and\ d=6$ in the sum formula to find the sum of first 30 terms.

Now, the sum of first 30 terms is given as:

$S_{30}=\frac{30}{2}(2(-15)+(30-1)(6))\\S_{30}=15(-30+29(6))\\S_{30}=15(-30+174)\\S_{30}=15(144)=2160$

Therefore, the sum of first 30 terms of the arithmetic progression is 2160.

4 0

3 years ago

First Name * hey can some one help

IRISSAK [1]

Answer:

1.VOLUME– The amount of space an object takes up. Basic Unit (SI Unit) for Solids – Cubic Meter, m3. LENGTH/DISTANCE – The measurement between two points.

2.one particle per cubic meter.

3.it means it is heavier

4.In a liquid the particles are still close together but a little further apart than in a solid.

5.In gases the particles are much further apart than in solids or liquids.

Explanation:

thats all i can type lol

3 0

3 years ago

You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.

Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of 0,4mol / L

100mL are 0,1L. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = 7,01 g of indole-3-acetic acid

Thus, you need 7,01 g of indole-3-acetic acid to generate your solution.

I hope it helps!

5 0

4 years ago