<span>9370 years
First, you need to determine how many half-lives the sample has undergone. Since 67.7% has been lost, that means that 100% - 67.7% = 32.3% has been retained. So calculate the logarithm to base 2 of 0.323:
log(0.323)/log(2) = -0.490797478/0.301029996 = -1.63039393
The number -1.63039393 tells you that 1.63039393 half-lives have occurred since the mastodon died. A quick sanity check will assure you that this is true. Because after 1 half live, there would be 50% of the carbon-14 remaining. And after another half life, there would be 25% of the original carbon-14 remaining. And since 32.3% is between 25% and 50%, the value of 1.63 half lives is quite reasonable. Now just multiply the number of half lives expended by the half life of carbon-14.
1.63039393 * 5750 = 9374.765097
Rounding to 3 significant figures gives us 9370 years.</span>
Answer:
4.3 x 10(d) J
Q= 400 x 45 x 0.233 = 4.419 kj
Explanation:
Not sure if this is what your looking for... hope it helps though :)
Lead sulfate is produced as a lead acid battery is discharged. Hope this helped!
Answer:
The correct answer is A.
Explanation:
Helium's Atomic Model has 2 Protons and 2 Neutrons, and on the outside it has 2 electrons circling around it.
For this problem, let's use the approach of dimensional analysis. This technique is done by cancelling out like units that appear both on the numerator and the denominator side. As a result, this technique will let you know that your final answer conforms to what parameter is asked. In this case, the final answer should be in mL. The solution is as follows:
14.5 mg * 1 mL/25 mg = 0.58 mL