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Luda [366]
3 years ago
12

a marble starts from rest down the inside of a bowl and rolls without slipping. at the bottom the surface changes to a frictionl

ess surface. The marble then moves up the other side to a certain height. Is this height higher, lower, or the same as the height from which the marble started
Physics
2 answers:
Angelina_Jolie [31]3 years ago
7 0

Answer:

The height will be the same.

Explanation:

At the top, the marble is at rest and the only energy it has is potential energy. As long as the marble is at the top of the container, the potential energy will be the same at any point and since it is at rest there will be no loss due to friction. It can be said that the height at which the marble will be raised will be the same as well.

vazorg [7]3 years ago
5 0

Answer:

The height will be lower.

Explanation:

The marble starts from a certain height with some potential energy and as it rolls down the bowl, the potential energy that it has is converted into kinetic energy as movement but it also loses some of it's total energy to the friction force between the marble and the surface of the bowl therefore when the marble reaches the bottom of the bowl, the total energy that it has is less than the energy it began with.

Even though the surface upwards is frictionless, the loss of energy from the downwards motion will result in the marble reaching a lower heigth than its first height when it began moving.

I hope this answer helps.

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Brainlist nd 20 points
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Answer:

I'm not sure but I think it's 35-39

4 0
3 years ago
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If an oscillating mass has a frequency of 1.25 Hz, it makes 100 oscillations in
KatRina [158]

Answer:

Time, t = 80 seconds

Explanation:

Given that,

The frequency of the oscillating mass, f = 1.25 Hz

Number of oscillations, n = 100

We need to find the time in which it makes 100 oscillations. We know that the frequency of an object is number of oscillations per unit time. It is given by :

f=\dfrac{n}{t}

t=\dfrac{n}{f}

t=\dfrac{100}{1.25\ Hz}

t = 80 seconds

So, it will make 100 oscillations in 80 seconds. Hence, this is the required solution.

4 0
3 years ago
If a car travels 30 mi. north for 30 min., 60 mi. east for 1.0 hour, and 30 mi. south for 30 min., what is the average speed
Ainat [17]

Answer: 60mph

Explanation:

Given the following :

First leg travel:

Distance = 30 miles

Time of travel= 30 minutes = 0.5 hour

Second leg travel:

Distance = 60 miles

Time of travel = one hour

Average speed :

Speed = total Distance / time of travel

Total distance in miles = (30 + 60) miles = 90 miles

Total time of travel = 1 hour + 0.5 hour = 1.5 hours

Average speed = total distance traveled / total travel time

Average speed = 90 miles / 1.5 hours

Average speed = 60 miles / hour

= 60mph

3 0
4 years ago
Which statement best describes the atoms of the gas neon?
Leya [2.2K]

Answer:

They:

-Are far from each others

-Move constantly

-Move freely (all directions)

-Move at high speed

5 0
3 years ago
Cart a having a mass of 150 kg initially moving to the right at a speed of 8 m/s collides with cart b with a mass of 150 kg, ini
kakasveta [241]

The speed of cart b is 6m/s while the total momentum of the systmen is 4200 kg m/s

<h3>Conservation of Linear Momentum</h3>

Given Data

  • Mass of cart one M1  = 150kg
  • Initial Velocity U1 = 8m/s
  • Final VelocityV1 = 5 m/s

Mass of cart two M2  = 150kg

Velocity U2 = 6m/s

Applying the principle of conservation of linear momentum we have

M1U1+M2U2 = M1V1+ M2V2

a. what is the speed of cart b after collision

substituting our given data we have

150*8+ 150*6 = 150*5+150*V2

1200 + 900 = 1200+ 150V2

2100 - 1200 = 150V2

900 = 150V2

Divide both sides by 150

V2 = 900/150

V2 = 6m/s

b. what is the total momentum of the system before and after collision

Total Momentum in the system is

Total momentum = Momentum before Impact+ Momentum after Impact

Total momentum = M1U1+M2U2 + M1V1+ M2V2

Total momentum = 1200 + 900 + 1200+ 900

Total momentum = 4200 kg m/s

Learn more about Conservation of Linear Momentum here:

brainly.com/question/7538238

6 0
2 years ago
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