A rock weighing 15.0g is placed in a graduated cylinder, displacing the volume from 25.0 mL to 36.2 mL. What is the density of t
2 answers:
Answer : The density of the rock is,
Explanation : Given,
Mass of the rock = 15 g
Initial volume = 25 ml
Increased volume = 36.2 ml
First we have to calculate the volume of the rock.
Volume of rock = Increased volume of water - Initial volume of water
Volume of rock = 36.2 ml - 25 ml = 11.2 ml
Now we have to calculate the density of rock.
Formula used :
Now put all the given values in this formula, we get the density of the rock.
Conversion :
Therefore, the density of the rock is,
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Answer:
Explanation:
We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.
The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.
- ΔT= final temperature - initial temperature
The sample was heated <em>from </em> 58.8 degrees Celsius to 88.9 degrees Celsius.
- ΔT= 88.9 °C - 58.8 °C = 30.1 °C
Now we know three variables:
- Q= 4500.0 J
- c= 0.4494 J/g°C
- ΔT = 30.1 °C
Substitute these values into the formula.
Multiply on the right side of the equation. The units of degrees Celsius cancel.
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g
The units of Joules cancel.
The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.
The mass of the sample of metal is approximately <u>333 grams.</u>